That would be the commutative property
Answer:
Theorem: The diagonals of a parallelogram bisect each other. Proof: Given ABCD, let the diagonals AC and BD intersect at E, we must prove that AE ∼ = CE and BE ∼ = DE. The converse is also true: If the diagonals of a quadrilateral bisect each other, then the quadrilateral is a parallelogram.
Step-by-step explanation:
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Answer:
cos(x) = 0.6
Step-by-step explanation:
First, we need to find UQ.
UQ = UP·cos(y°) = UP·√(1 -sin²(y°)) = (26 cm)√(1 -25/169) = (26 cm)(12/13)
UQ = 24 cm
Then TQ is ...
TQ = 1/3UQ = 1/3(24 cm) = 8 cm
And cos(x°) is ...
cos(x°) = √(1 -sin²(x)) = √(1 -64/100)
cos(x°) = 6/10 = 3/5
cos(x°) = 3/5 = 0.6
Answer:
a = M -Gh/G
Step-by-step explanation:
in order to make a the subject of fomular , you will open the bracket first and then combine the like terms.
G(a + h) = M
Ga + Gh = M
Ga = M - Gh
since G is disturbing a from standing alone, we divide both sides by G
Ga/G = M- Gh/ G
a = M -Gh/G
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Hope this helps!
