Given the geometric sequence where a1=1 and the common ratio is 6, what is the domain for n?
1 answer:
We have been given that a geometric sequence's 1st term is equal to 1 and the common ratio is 6. We are asked to find the domain for n.
We know that a geometric sequence is in form , where,
= nth term of sequence,
= 1st term of sequence,
r = Common ratio,
n = Number of terms in a sequence.
Upon substituting our given values in geometric sequence formula, we will get:
Our sequence is defined for all integers such that n is greater than or equal to 1.
Therefore, domain for n is all integers, where .
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Answer:
x = 2root(22)
see image.
Step-by-step explanation:
The triangle shown is one big triangle cut into two more smaller triangles: one medium-sized and one smaller.
ALL THREE TRIANGLES ARE SIMILAR BY AA.
Set the two smaller triangles up so you can see the corresponding sides. x is the short leg in one triangle and it is the long leg in the smallest triangle. Set up a proportion.
22/x = x/4
crossmultiply
x^2 = 22•4
x^2 = 88
square root both sides.
x = sqroot(88)
x = 2sqroot(22)
see image.
