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3 years ago

I need help on iready

Mathematics

1 answer:

kicyunya [14]3 years ago

7 0

Answer:

the answer is 3

Step-by-step explanation:

because if you do the methoes method you know that it rules out 1 and 2 after you do that its just between 3 and 4, for the caunususicon there has to be one, that is why i think its 3. hope this helps!

You might be interested in

Find the area of the triangle that is half of the rectangle:: Which option is it ?????

Dovator [93]

12 x 8 = 96
96/2 = 48

it's an area equation so 48 m^2

3 0

3 years ago

Read 2 more answers

A passenger rode the subway 2 blocks west and then 10 south. If all the blocks are the same length what is the value of the slop

Nimfa-mama [501]

Answer:

The slope of the line is 5

Step-by-step explanation:

Great question, it is always good to ask away and get rid of any doubts that you may be having.

I have created an illustration which is attached below in order to help you understand the situation. As we are told the passenger rode the subway from point (0 , 0) to point (-2, 0). Then he rode the subway from point (-2, 0) to the final destination of point (-2 , -10). In order to find the value of the slope we need to use the slope formula which is

$Slope = \frac{y_{2}-y_{1} }{x_{2}- x_{1} }$

Now we just plug in the values of the starting point and final destination in order to find the slope of the line.

$Slope = \frac{(-10) - (0)}{(-2)-(0)}$

$Slope = \frac{-10}{-2}$

$Slope =5$

Finally we can see that the slope of the line is 5

I hope this answered your question. If you have any more questions feel free to ask away at Brainly.

6 0

3 years ago

A product can be made in sizes huge, average and tiny which yield a net unit profit of $14, $10, and$5, respectively. Three cent

navik [9.2K]

Answer:

The model is:

z = 14* X₁₁ + 14*X₁₂ + 5*X₁₃ + 10*X₂₁ + 10*X₂₂ + 10*X₂₃ + 5*X₃₁ + 5*X₃₂ + 5*X₃₃ to maximize

Subject to:

First center X₁₁ + X₂₁ + X₃₁ ≤ 550

Second center X₁₂ + X₂₂ + X₃₂ ≤ 750

Third center X₁₃ + X₂₃ + X₃₃ ≤ 275

22* X₁₁ + 16* X₂₁ + 9*X₃₁ ≤ 11000

22* X₁₂ + 16* X₂₂ + 9*X₃₂ ≤ 2700

22*X₁₃ + 16* X₂₃ + 9*X₃₃ ≤ 3400

X₁₁ + X₁₂ + X₁₃ ≤ 710

X₂₁ + X₂₂ + X₂₃ ≤ 900

X₃₁ + X₃₂ + X₃₃ ≤ 350

2700*(X₁₁ + X ₂₁ + X₃₁) - 11000*(X₁₂ + X₂₂ + X₃₂) = 0

3400*(X₁₁ + X ₂₁ + X₃₁) - 11000*( ( X₁₃ + X₂₃ + X₃₃) = 0

Xij >= 0

Step-by-step explanation:

Let´s call Xij product size i produced in center j

According to this, we get the following set of variable

X₁₁ product size huge produced in center 1

X₁₂ product size huge produced in center 2

X₁₃ product size huge produced in center 3

X₂₁ product size average produced in center 1

X₂₂ product size average produced in center 2

X₂₃ product size average produced in center 3

X₃₁ product size-tiny produced in center 1

X₃₂ product size-tiny produced in center 2

X₃₃ product size-tiny produced in center 3

Then Objective function is

z = 14* X₁₁ + 14*X₁₂ + 5*X₁₃ + 10*X₂₁ + 10*X₂₂ + 10*X₂₃ + 5*X₃₁ + 5*X₃₂ + 5*X₃₃

Constrains

Center capacity

1.- First center X₁₁ + X₂₁ + X₃₁ ≤ 550

2.- Second center X₁₂ + X₂₂ + X₃₂ ≤ 750

3.- Third center X₁₃ + X₂₃ + X₃₃ ≤ 275

Water available

1.- 22* X₁₁ + 16* X₂₁ + 9*X₃₁ ≤ 11000

2.- 22* X₁₂ + 16* X₂₂ + 9*X₃₂ ≤ 2700

3.- 22*X₁₃ + 16* X₂₃ + 9*X₃₃ ≤ 3400

Demand constrain

Product huge

X₁₁ + X₁₂ + X₁₃ ≤ 710

Product average

X₂₁ + X₂₂ + X₂₃ ≤ 900

Product tiny

X₃₁ + X₃₂ + X₃₃ ≤ 350

Fraction SP/CC must be the same

First and second centers fraction SP/CC

(X₁₁ + X ₂₁ + X₃₁)/ 11000 = (X₁₂ + X₂₂ + X₃₂)/ 2700

2700*(X₁₁ + X ₂₁ + X₃₁) - 11000*(X₁₂ + X₂₂ + X₃₂) = 0

First and third centers fraction SP/CC

(X₁₁ + X ₂₁ + X₃₁)/ 11000 = ( X₁₃ + X₂₃ + X₃₃)/ 3400

3400*(X₁₁ + X ₂₁ + X₃₁) - 11000*( ( X₁₃ + X₂₃ + X₃₃) = 0

The model is:

z = 14* X₁₁ + 14*X₁₂ + 5*X₁₃ + 10*X₂₁ + 10*X₂₂ + 10*X₂₃ + 5*X₃₁ + 5*X₃₂ + 5*X₃₃

Subject to:

First center X₁₁ + X₂₁ + X₃₁ ≤ 550

Second center X₁₂ + X₂₂ + X₃₂ ≤ 750

Third center X₁₃ + X₂₃ + X₃₃ ≤ 275

22* X₁₁ + 16* X₂₁ + 9*X₃₁ ≤ 11000

22* X₁₂ + 16* X₂₂ + 9*X₃₂ ≤ 2700

22*X₁₃ + 16* X₂₃ + 9*X₃₃ ≤ 3400

X₁₁ + X₁₂ + X₁₃ ≤ 710

X₂₁ + X₂₂ + X₂₃ ≤ 900

X₃₁ + X₃₂ + X₃₃ ≤ 350

2700*(X₁₁ + X ₂₁ + X₃₁) - 11000*(X₁₂ + X₂₂ + X₃₂) = 0

3400*(X₁₁ + X ₂₁ + X₃₁) - 11000*( ( X₁₃ + X₂₃ + X₃₃) = 0

Xij >= 0

6 0

3 years ago

The low temperatures in Anchorage, Alaska, for a week were − 6, − 3, − 1, 1, − 3, − 9, and − 14 degrees Celsius. What two temper

Inessa05 [86]

The two temperatures could be removed so that the average of the remaining numbers is the same as the average of the original set of numbers are -1 and -9

Step-by-step explanation:

The formula of the average of a set of data is $A=\frac{S}{N}$ , where

S is the sum of the data in the set
N is the number of the data in the set

∵ The low temperatures in Anchorage, Alaska, for a week were

− 6, − 3, − 1, 1, − 3, − 9, and − 14 degrees Celsius

∴ The set of the data is { -6 , -3 , -1 , 1 , -3 , -9 , -14}

- Add the data in the set

∵ S = -6 + -3 + -1 + 1 + -3 + -9 + -14

∴ S = -35

∵ The set has 7 data

∴ N = 7

- Use the formula of the average above to find it

∴ $A=\frac{-35}{7}$

∴ A = -5

∴ The average of the original set of numbers is -5

To keep the average the same after removing two numbers multiply the average by the new number of data to find the new sum

∵ The number of data after removing two numbers is 5

∴ N = 5

∵ A = -5

- By using the rule of average

∴ $-5=\frac{S}{5}$

- Multiply both sides by 5

∴ -25 = S

∴ The new sum is -25

- Lets find which two numbers of have a sum of -10 because

the difference between -35 and -25 is -10

∵ -1 + -9 = -10

∵ -6 + -3 + 1 + -3 + -14 = -25

∴ We could removed -1 and -9

The two temperatures could be removed so that the average of the remaining numbers is the same as the average of the original set of numbers are -1 and -9

Learn more:

You can learn more about the average in brainly.com/question/10764770

#LearnwithBrainly

7 0

3 years ago

PLEASE HELP ME WITH Q 1. a) b)

diamong [38]

A calculate the bounce height for each and work out the total

b do it again and use a stopwatch and calulate. Hope this helped

6 0

3 years ago