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zhannawk [14.2K]
3 years ago
10

Let R be the region bounded by the graph of

heta%5E%7B2%7D%20%29" id="TexFormula1" title="r=(theta) = s\sqrt{theta}sin(theta^{2} )" alt="r=(theta) = s\sqrt{theta}sin(theta^{2} )" align="absmiddle" class="latex-formula"> for 0\leq Θ \leq \sqrt{pi}

Advanced Placement (AP)
1 answer:
irakobra [83]3 years ago
8 0

Answer:

reeeeeeeeeeeeeeeignrirrirbrj yes

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Alex

Answer:

E. \angle 3 and \angle 5.

Explanation:

According to the figure, we have the following conclusions:

1) \angle 1 and \angle 2 are vertical opposite angles. (m \angle 1 = m \angle 2)

2) \angle 2 and \angle 3 are internal alternate angles. (m \angle 2 = m\angle 3)

3) \angle 2 and \angle 4 are corresponding angles. (m\angle 2 = m\angle 4)

4) \angle 3 and \angle 4 are vertical opposite angles. (m \angle 3 = m \angle 4)

But, \angle 3 and \angle 5, since m \angle 3 + m\angle 6 + m\angle 5 = 180^{\circ}, where \angle 3 is an acute angle and \angle 6 is a right angle, and m \angle 4 + m \angle 5 = 90^{\circ}. Then,

m\angle 5 = 90^{\circ} -m\angle 4.

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3 years ago
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Therefore, your answer is D.Using tobacco after you turn 18

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