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Mrrafil [7]
3 years ago
6

Help! I need somebody

Mathematics
1 answer:
oee [108]3 years ago
6 0

Answer:

t to the sixth power equals 9

t=1.5

Step-by-step explanation:

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Answer:

D trust me look

Step-by-step explanation:

Hope This Helped

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3 years ago
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How can a lack of understanding of the measures of central tendency and variability affect business decisions
polet [3.4K]
The measure of central tendency give you a picture of what to expect in a situation. For example, a basketball players average is the amount of points that they typical score.

In a business, you make decisions on what you expect to happen. Knowing the measure of center can help you make better decisions.
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Consider the equation below. log Subscript 4 Baseline (x + 3) = log Subscript 2 Baseline (2 + x) Which system of equations can r
natta225 [31]

Answer:

Using: loga b = log b / log a

1) a=x+3, b=4 → y1=log4 (x+3) → y1= log (x+3) / log 4

2) a=2+x, b=2 →y2=log2 (2+x) → y2=log (2+x) / log 2

Answer:

y1=log (x+3) / log 4, y2= log (2+x) / log 2

Step-by-step explanation:

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4 years ago
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The population in Smalltown in 2010 was 47,597 people and is growing exponentially at a rate of 1.8 percent. Which of the follow
ValentinkaMS [17]

Given Information:

Starting population = P₀ = 47,597

rate of growth = 1.8%

Required Information:

Equation that defines the population t years = ?

Answer:

The following equation defines the population t years after 2010.

$ P(t) = 47,597e^{0.018t} $

Step-by-step explanation:

The population growth can be modeled as an exponential function,

$ P(t) = P_0e^{rt} $  

Where P₀ is the starting population in 2010, r is the rate of growth of the population and t is the time in years after 2010.

We are given that the starting population is 47,597 and rate of growth is 1.8%

So the population function becomes

$ P(t) = 47,597e^{0.018t} $

Therefore, the above function may be used to estimate the population for t   years after 2010.

For example:

What is the population after 10 years?

For the given case,

t = 10

$ P(10) = 47,597e^{0.018(10)} $

$ P(10) = 47,597e^{0.18}$

$ P(10) = 47,597(1.1972)$

$ P(10) = 56,984

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3 years ago
Two numbers have a difference of 0.85 and a sum of 1 what are the numbers
never [62]
They are .925 and .075
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