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irina1246 [14]
2 years ago
6

Due Tomorrow at 4 help me

Mathematics
2 answers:
RideAnS [48]2 years ago
6 0

Answer:

question 1: option C (1)

question 2: option A (3)

Step-by-step explanation:

hope it helps!

Alik [6]2 years ago
4 0

Answer:

1- 1

2-3

3- -1/8

Step-by-step explanation:

I used a calculator :/

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#6: Tell whether the function below is 1 point<br> linear or exponential.<br> *<br> f(x) = -1/4x + 5
Pachacha [2.7K]

Answer:

Linear function

Step-by-step explanation:

Given

f(x) = -\frac{1}{4}x + 5

Required

Linear or Exponential

A linear equation has the form: f(x) = mx + c;

An exponential has the form: f(x) = ab^x

By comparing both functions to: f(x) = -\frac{1}{4}x + 5

The linear function is similar to f(x) = -\frac{1}{4}x + 5

<em>Hence, the given function is a linear function.</em>

8 0
3 years ago
What is 89.99 divided by 30%
kirill115 [55]

Answer:

if you are dividing 299.96 If you are multiplying 26.99

Step-by-step explanation:

If you are dividing: Factor the numerator and denominator and cancel the common factors.

If you are multiplying: Simplify the expression.

6 0
3 years ago
Read 2 more answers
Two competitive neighbours build rectangular pools that cover the same area but are different shapes. Pool A has a width of (x +
GenaCL600 [577]

<u>Answer: </u>

a)Dimensions of pool A are length = 6.667m and width = 3.667 m and dimension of pool B are length = 7.333m and width = 3.333m.

b) Area of pool A is equal to area of pool B equal to 24.44 meters.

<u> Solution: </u>

Let’s first calculate area of pool A .

Given that width of the pool A = (x+3)  

Length of the pool A is 3 meter longer than its width.

So length of pool A = (x+3) + 3 =(x + 6)

Area of rectangle = length x width

So area of pool A =(x+6) (x+3)        ------(1)

Let’s calculate area of pool B

Given that length of pool B is double of width of pool A.

So length of pool B = 2(x+3) =(2x + 6) m

Width of pool B is 4 meter shorter than its length,

So width of pool B = (2x +6 ) – 4 = 2x + 2

Area of rectangle = length x width

So area of pool B =(2x+6)(2x+2)        ------(2)

Since area of pool A is equal to area of pool B, so from equation (1) and (2)

(x+6) (x+3) =(2x+6) (2x+2)    

On solving above equation for x    

(x+6) (x+3) =2(x+3) (2x+2)  

x+6 = 4x + 4    

x-4x = 4 – 6

x = \frac{2}{3}

Dimension of pool A

Length = x+6 = (\frac{2}{3}) +6 = 6.667m

Width = x +3 = (\frac{2}{3}) +3 = 3.667m

Dimension of pool B

Length = 2x +6 = 2(\frac{2}{3}) + 6 = \frac{22}{3} = 7.333m

Width = 2x + 2 = 2(\frac{2}{3}) + 2 = \frac{10}{3} = 3.333m

Verifying the area:

Area of pool A = (\frac{20}{3}) x (\frac{11}{3}) = \frac{220}{9} = 24.44 meter

Area of pool B = (\frac{22}{3}) x (\frac{10}{3}) = \frac{220}{9} = 24.44 meter

Summarizing the results:

(a)Dimensions of pool A are length = 6.667m and width = 3.667 m and dimension of pool B are length = 7.333m and width = 3.333m.

(b)Area of pool A is equal to Area of pool B equal to 24.44 meters.

5 0
3 years ago
An Isosceles triangle is shown below. What is the size of angle a°.
Sergeeva-Olga [200]

Step-by-step explanation:

without seeing a picture I'm guessing 45 45, and 90

4 0
2 years ago
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2(-6)2 – 3(8) + 4(-6)2
Llana [10]

Answer:

-96

Hope this helps ya out!

4 0
2 years ago
Read 2 more answers
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