1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
wlad13 [49]
3 years ago
14

What is the factorization of the polynomial below? 9x2 - 16

Mathematics
2 answers:
Agata [3.3K]3 years ago
8 0

use (a-b) (a+b )

(3x+4) (3x- 4)

saul85 [17]3 years ago
3 0
<h3><u>Answer</u><u>:</u><u>-</u></h3>

\bigcirc(9x+4)(x-4)

\bigcirc(9x-4)(x-4)

\odot(3x+4)(3x-4)

\bigcirc(3x-4)(3x-4)

<h2>_____________________</h2><h3><u>Calculations</u><u>:</u><u>-</u></h3>

<h2><u>Let's</u><u> </u><u>Factori</u><u>s</u><u>e</u><u>:</u><u>-</u></h2>

{:}\leadsto \sf 9x^2-16

  • Let's use algebraic identity for factorisation

{\boxed{\sf (a+b)(a-b)=(a)^2-(b)^2}}

  • Here see 16 is the square of 4 and 9x^2 is the square of 3x

{:}\leadsto \sf 3x^2-4^2

  • Now According to identity

{:}\leadsto \sf (3x+4)(3x-4)

<h3>Hence the correct option is option C.</h3>

You might be interested in
A chapter begins on page 114 and ends on page 859. How many pages are in the chapter?
Usimov [2.4K]
745, because u need to subtract both to find pages isolated
3 0
3 years ago
Read 2 more answers
20 and 1/2 x 10 1/4 x 12
Andru [333]

Answer:

2521.5

Step-by-step explanation:

20.5 · 10.25 · 12

2521.5

5 0
3 years ago
What is ...
Brut [27]
\dfrac{14+a}{13}=12
14+a=13\cdot 12
14+a=156
a=156-14
\boxed{a=142}
8 0
3 years ago
Graph the inequality on a number line. s &lt; 1 1/2
ValentinkaMS [17]

Step-by-step explanation:

Put a open circle at 1 1/2 then draw a line going to the left of 1 1/2

5 0
2 years ago
I need help ASAP! Can anyone please check my work?
STALIN [3.7K]

A = event the person got the class they wanted

B = event the person is on the honor roll

P(A) = (number who got the class they wanted)/(number total)

P(A) = 379/500

P(A) = 0.758

There's a 75.8% chance someone will get the class they want

Let's see if being on the honor roll changes the probability we just found

So we want to compute P(A | B). If it is equal to P(A), then being on the honor roll does not change P(A).

---------------

A and B = someone got the class they want and they're on the honor roll

P(A and B) = 64/500

P(A and B) = 0.128

P(B) = 144/500

P(B) = 0.288

P(A | B) = P(A and B)/P(B)

P(A | B) = 0.128/0.288

P(A | B) = 0.44 approximately

This is what you have shown in your steps. This means if we know the person is on the honor roll, then they have a 44% chance of getting the class they want.

Those on the honor roll are at a disadvantage to getting their requested class. Perhaps the thinking is that the honor roll students can handle harder or less popular teachers.

Regardless of motivations, being on the honor roll changes the probability of getting the class you want. So Alex is correct in thinking the honor roll students have a disadvantage. Everything would be fair if P(A | B) = P(A) showing that events A and B are independent. That is not the case here so the events are linked somehow.

8 0
3 years ago
Other questions:
  • Compare decimals 0. 7 and 0. 6 9 9 9 is it A&lt; be &gt;. c​
    6·1 answer
  • In the transmission of digital information, the probability that a bit has high, moderate, and low distortion is 0.02, 0.07, and
    6·1 answer
  • Can someone pls tell me how to solve this
    9·2 answers
  • The following triangles are similar. Find side AB.
    8·2 answers
  • How do u solve 3y-4=6-2y3y-4=6-2y
    15·1 answer
  • 4/5 = 28/x <br><br> x= <br> i need to know what x =
    14·1 answer
  • Help me, please<br> i really need it
    10·2 answers
  • 6x + 8 = 5x - 7 solve for x plssss
    8·1 answer
  • When does a limit exist.
    10·1 answer
  • Raymond’s gas tank is 1/3 full. After he buys 11 gallons of gas, it is 5/6 full. How many gallons can Raymond’s tank hold?
    9·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!