Question

What is the factorization of the polynomial below? 9x2 - 16

Answer 1

use (a-b) (a+b )

(3x+4) (3x- 4)

Answer 2

Answer:-

$\bigcirc$(9x+4)(x-4)

$\bigcirc$(9x-4)(x-4)

$\odot$(3x+4)(3x-4)

$\bigcirc$(3x-4)(3x-4)

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Calculations:-

Let's Factorise:-

${:}\leadsto$ $\sf 9x^2-16$

• Let's use algebraic identity for factorisation

${\boxed{\sf (a+b)(a-b)=(a)^2-(b)^2}}$

• Here see 16 is the square of 4 and 9x^2 is the square of 3x

${:}\leadsto$ $\sf 3x^2-4^2$

• Now According to identity

${:}\leadsto$ $\sf (3x+4)(3x-4)$

Hence the correct option is option C.