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malfutka [58]
3 years ago
10

3MIN LEFT PLEASE HELP ME FAST

Mathematics
1 answer:
Lapatulllka [165]3 years ago
5 0

226

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Find the total volume. Please show your work.​
elena-s [515]

Answer:

Step-by-step explanation:

You have a half sphere and a cylinder.

Trick question! Note that the diameter of the cylinder is in meters, while the height is given in centimeters.

For cylinder:

 radius r = 5 m

 height h = 6 cm = 0.06 m

 volume = πr²h = π(5²)(0.06) = 1.5π m³

For sphere:

 radius r = 5 m

 volume of sphere = (4/3)πr³

 volume of half sphere =  (2/3)πr³ = (2/3)π5³ = (250/3)π m³

Total volume = 1.5π + 250π/3 ≅ 266.5 m³

4 0
2 years ago
Joe has 4/5 as much money as bob. Tim has $50 more than joe. Rita has $150, which is $35 more than bob. How much money does tim
lesantik [10]

Rita = $150

Bob = $150 - $35 = $115    Bob has $115

Joe = $115 divided by 5 = $23      $23 x 4 = $92    Joe Has $92

Tim = Has $50 more then joe, $92 + $50 = $142     Tim has $142

3 0
3 years ago
What year is 7 years after 2003
mezya [45]

Answer:

2010

Step-by-step explanation:

6 0
2 years ago
Read 2 more answers
A laboratory scale is known to have a standard deviation (sigma) or 0.001 g in repeated weighings. Scale readings in repeated we
weqwewe [10]

Answer:

99% confidence interval for the given specimen is [3.4125 , 3.4155].

Step-by-step explanation:

We are given that a laboratory scale is known to have a standard deviation (sigma) or 0.001 g in repeated weighing. Scale readings in repeated weighing are Normally distributed with mean equal to the true weight of the specimen.

Three weighing of a specimen on this scale give 3.412, 3.416, and 3.414 g.

Firstly, the pivotal quantity for 99% confidence interval for the true mean specimen is given by;

        P.Q. = \frac{\bar X - \mu}{\frac{\sigma}{\sqrt{n} } } ~ N(0,1)

where, \bar X = sample mean weighing of specimen = \frac{3.412+3.416+3.414}{3} = 3.414 g

            \sigma = population standard deviation = 0.001 g

            n = sample of specimen = 3

            \mu = population mean

<em>Here for constructing 99% confidence interval we have used z statistics because we know about population standard deviation (sigma).</em>

So, 99% confidence interval for the population​ mean, \mu is ;

P(-2.5758 < N(0,1) < 2.5758) = 0.99  {As the critical value of z at 0.5% level

                                                            of significance are -2.5758 & 2.5758}

P(-2.5758 < \frac{\bar X - \mu}{\frac{\sigma}{\sqrt{n} } } < 2.5758) = 0.99

P( -2.5758 \times {\frac{\sigma}{\sqrt{n} } } < {\bar X - \mu} < 2.5758 \times {\frac{\sigma}{\sqrt{n} } } ) = 0.99

P( \bar X-2.5758 \times {\frac{\sigma}{\sqrt{n} } } < \mu < \bar X+2.5758 \times {\frac{\sigma}{\sqrt{n} } } ) = 0.99

<u>99% confidence interval for</u> \mu = [ \bar X-2.5758 \times {\frac{\sigma}{\sqrt{n} } } , \bar X+2.5758 \times {\frac{\sigma}{\sqrt{n} } } ]

                                             = [ 3.414-2.5758 \times {\frac{0.001}{\sqrt{3} } } , 3.414+2.5758 \times {\frac{0.001}{\sqrt{3} } } ]

                                             = [3.4125 , 3.4155]

Therefore, 99% confidence interval for this specimen is [3.4125 , 3.4155].

6 0
3 years ago
Answer my question please help
Alchen [17]

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I ᕼOᑭᗴ IT ᕼᗴᒪᑭՏ

ǝɹnsʇouɯᴉ#

6 0
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