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IrinaVladis [17]
3 years ago
5

I need help again if I don't get this right then I'll have to do the lesson all over again and I'm already 10 lessons behind!

Mathematics
2 answers:
xxTIMURxx [149]3 years ago
6 0
<h3>♫ - - - - - - - - - - - - - - - ~<u>Hello There</u>!~ - - - - - - - - - - - - - - - ♫</h3>

➷ It would be option D

<h3><u>✽</u></h3>

➶ Hope This Helps You!

➶ Good Luck (:

➶ Have A Great Day ^-^

↬ ʜᴀɴɴᴀʜ ♡

11Alexandr11 [23.1K]3 years ago
3 0

Answer: D

Step-by-step explanation:

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What is the sum of an infinite geometric series if the first term is 156 and the common ratio is 2⁄3?
Zanzabum

Answer:

<h2>B. 468</h2>

Step-by-step explanation:

We have

a_1=156,\ r=\dfrac{2}{3}

If |r| < 1, then the formula of a sum of an infinite geometric sequence is:

S=\dfrac{a_1}{1-r}

Substitute:

S=\dfrac{156}{1-\frac{2}{3}}=\dfrac{156}{\frac{1}{3}}=156\cdot\dfrac{3}{1}=468

4 0
3 years ago
Use the factors of the function and the y-intercept to find the standard form of the equation representing Jared’s function. Typ
Georgia [21]

The y-intercept of a function is the point where the graph crosses the \mathbf{y = x^3 + 2x^2 - 193x - 270 }

  • The factors of the Jared's graph are: (x - 10), (x + 3) and (x + 9)
  • The y-intercept is -13.5
  • The standard equation of the function is: \mathbf{y = x^3 + 2x^2 - 193x - 270 }

<u>(a) The factors</u>

First, we write out the points where the function cross the x-axis.

The points are:

\mathbf{x = 10}

\mathbf{x = -3}

\mathbf{x = -9}

Equate the above points to 0

\mathbf{x -10 = 0}

\mathbf{x +3 = 0}

\mathbf{x +9 = 0}

Hence, the factors are: (x - 10), (x + 3) and (x + 9)

<u>(b) The y-intercept</u>

This is the point where the graph crosses the y-axis.

From the attached graph, the graph crosses the y-axis at -13.5.

Hence, the y-intercept is -13.5

<u>(c) The standard form</u>

In (a), we have:

\mathbf{x -10 = 0}

\mathbf{x +3 = 0}

\mathbf{x +9 = 0}

Multiply the above equations

\mathbf{(x - 10) \times (x + 3) \times (x + 9) = 0 \times 0 \times 0}

\mathbf{(x - 10) \times (x + 3) \times (x + 9) = 0 }

Expand

\mathbf{(x - 10) \times (x^2 + 3x + 9x + 27) = 0 }

\mathbf{(x - 10) \times (x^2 + 12x + 27) = 0 }

Expand

\mathbf{x^3 + 12x^2 + 27x - 10x^2 - 220x - 270 = 0 }

Collect like terms

\mathbf{x^3 + 12x^2 - 10x^2+ 27x  - 220x - 270 = 0 }

\mathbf{x^3 + 2x^2 - 193x - 270 = 0 }

Replace 0 with y

\mathbf{y = x^3 + 2x^2 - 193x - 270 }

Hence, the standard form is: \mathbf{y = x^3 + 2x^2 - 193x - 270 }

Read more about graphs and functions at:

brainly.com/question/18806107

3 0
3 years ago
What is the center of the hyperbola whose equation is (y+3)^2/81 - (x-6) ^2/89= 1?
GarryVolchara [31]

Answer:

I think its (6,-3)

Step-by-step explanation:

8 0
3 years ago
Jack and his children went into a restaurant where they sell hamburgers for $6 each and tacos for $2 each. Jack has $30 to spend
irina [24]
128..........................................
4 0
3 years ago
Read 2 more answers
What is -|-4| equal to?
goblinko [34]
Simple, it is equal to |4|, you have to draw the lines around the 4 on the worksheet.
4 0
3 years ago
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