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Anna35 [415]
3 years ago
11

Need help QUICKLYY ———————————————————

Mathematics
1 answer:
SashulF [63]3 years ago
5 0

Answer: a. g(x) = 3^x + 2 b. y = 3 c. same graph but shifted two units up

Step-by-step explanation:

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Find the sum of 6 terms in the sequence 3,6,12, ...
ira [324]
ANSWER!
93

EXPLANATION!

The sequence is doubling every number, so it would continue as

3,6,12,24,48

Now you are finding the sum, so addition. All you need to do now is add all those numbers.

3+6+12+24+48=93
8 0
1 year ago
PLEASE HELP MEEEEEEE
wolverine [178]

Answer:

(c)y= -1/3x+1

Step-by-step explanation:

it is the answer

8 0
3 years ago
PLLZ HELP Lenny is 3 times older then Max. When you subtract Max's age from Lenny's age, you get 24. How old is Lenny and how ol
kifflom [539]
Lenny is 36 max is 12
6 0
3 years ago
Read 2 more answers
A solid lies between planes perpendicular to the x-axis at x tox=. The cross sections perpendicular to the x-axis are circular d
cluponka [151]

It's unclear what the planes are supposed to be, so I'll take x=a and x=b with 0\le a.

The cross sections are disks with diameter \csc x-\cot x, so each disk of thickness \Delta x has a volume of

\dfrac{\pi(\csc x-\cot x)^2}4\Delta x

Then taking infinitesimally thin disks, we find the solid has a volume of

\displaystyle\frac\pi4\int_a^b(\csc x-\cot x)^2\,\mathrm dx

Since

(\csc x-\cot x)^2=2\csc^2x-2\csc x\cot x-1

and

\dfrac{\mathrm d(\csc x)}{\mathrm dx}=-\csc x\cot x

\dfrac{\mathrm d(\cot x)}{\mathrm dx}=-\csc^2x

it follows that the volume is

\displaystyle\frac\pi4\left(-2\cot x+2\csc x-x\right)\bigg|_a^b

=\dfrac\pi4(2(\cot a-\cot b)+2(\csc b-\csc a)+a-b)

=\dfrac\pi4\left(2\tan\dfrac b2-2\tan\dfrac a2+a-b\right)

3 0
3 years ago
Find all the zeros of the polynomial x^4+x^3-34x^2-4x+120 if two of its zeros are 2,-2
miskamm [114]

Answer:

The zeroes are 2, -2, -6, 5.

Step-by-step explanation:

If 2 of the zeroes are 2 and -2 then (x - 2)(x + 2) is factor of the polynomial.

We can now do long division.

Note (x - 2)(x + 2) = x^2 - 4, so we have:

x^2 - 4 ( x^4 + x^3 - 34x^2 - 4x + 120 ( x^2 +   x  - 30 <--- Quotient

             x^4            - 4x^4

                      x^3 -  30x^2 - 4x

                      x^3                -4x

                                  -30x^2   + 120  

                                  -30x^2   + 120

                                           

x^2 +   x  - 30 = 0        

(x + 6)(x - 5) = 0

x = -6, 5.              

7 0
2 years ago
Read 2 more answers
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