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yulyashka [42]
3 years ago
15

In ΔSTU, the measure of ∠U=90°, US = 7.3 feet, and ST = 9.8 feet. Find the measure of ∠S to the nearest tenth of a degree.

Mathematics
1 answer:
Orlov [11]3 years ago
4 0

Answer:41.8

Step-by-step explanation:

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!!!! will give brainliest:
Nataly [62]

Answer:

the domain will be all real #'s bc the arrows are continuous/never ending. The range would be y<u><</u>4 because the line starts at 4 and goes down.

Hope this helped you :)

4 0
3 years ago
6⋅[(32−8)÷4+2] What is the answer to this expession?
Nimfa-mama [501]

Answer:

48

Step-by-step explanation:

=6*[24/4+2]

=6*[6+2]

=6*8

=48

4 0
3 years ago
The Marked price of a jacket at a dealer's shop is 2400. The dealer allows a discount of 15% to the retailer. As the company's p
Andrej [43]

Answer:

2400

2640

360

Step-by-step explanation:

the retailer has to sell it for the same price as the dealer.

so, both mark it for 2400 sale price.

if a customer buys it at the retailer, the retailer makes the 15% discount he got from the dealer as profit.

2400 = 100%

1% = 2400/100 = 24

15% = 24×15 = 360

the retailer makes this profit no matter what other fees or taxes are added.

the final price is then including 10% VAT

2400 = 100%

10% = 24×10 = 240

final price = SP + VAT = 2400 + 240 = 2640

6 0
3 years ago
A credit card company charges 22% interest fee on any charges not paid at the end of the month.. If the bill totals $450 for thi
kifflom [539]
I think the answer is 450x .22= 99$
6 0
3 years ago
Alabama Instruments Company has set up a production line to manufacture a new calculator. The rate of production of these calcul
umka21 [38]

Answer:

The number of calculators is 4871

Step-by-step explanation:

If we integrate dx/dt we get x, which is the number of calculators. To find the number of calculators between the beginning of third week to the end of fourth week (the beginning of fifth week), this integration must be evaluated at t between 3 and 5.

x=\int\limits^5_3 {\frac{dx}{dt}} \, dt =\int\limits^5_3 {5000(1-\frac{100}{(t+10)^2})} \, dt

the result of the integration is:

x=5000(t+\frac{100}{t+10}) to be evaluated between 3 and 5, which is:

x=5000(5+\frac{100}{5+10})-5000(3+\frac{100}{3+10})=\frac{190000}{39}=4871.8

6 0
3 years ago
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