Answer:
Two complex (imaginary) solutions.
Step-by-step explanation:
To determine the number/type of solutions for a quadratic, we can evaluate its discriminant.
The discriminant formula for a quadratic in standard form is:
We have:
Hence, a=3; b=7; and c=5.
Substitute the values into our formula and evaluate. Therefore:
Hence, the result is a negative value.
If:
- The discriminant is negative, there are two, complex (imaginary) roots.
- The discriminant is 0, there is exactly one real root.
- The discriminant is positive, there are two, real roots.
Since our discriminant is negative, this means that for our equation, there exists two complex (imaginary) solutions.
Answer:
420
Step-by-step explanation:
We can find the prime factors of each of the numbers first before finding their LCM.
12: <em>2</em> × 2 × <u>3</u>
30: <em>2</em> × <u>3</u> × 5
42: <em>2</em> × <u>3</u> × 7
To find the LCM, we need to see if they are any common prime factors between all three numbers. The common prime factors are <em>2</em> and <u>3</u>. Then, we multiply 2 and 3 with the remaining outstanding factors, which are 2, 5, and 7.
LCM: <em>2</em> × 2 × <u>3</u> × 5 × 7 = 420
We have that
<span>(c-4)/(c-2)=(c-2)/(c+2) - 1/(2-c)
</span>- 1/(2-c)=-1/-(c-2)=1/(c-2)
(c-4)/(c-2)=(c-2)/(c+2)+ 1/(c-2)------- > (c-4)/(c-2)-1/(c-2)=(c-2)/(c+2)
(c-4-1)/(c-2)=(c-2)/(c+2)---------------- > (c-5)/(c-2)=(c-2)/(c+2)
(c-5)/(c-2)=(c-2)/(c+2)------------- > remember (before simplifying) for the solution that c can not be 2 or -2
(c-5)*(c+2)=(c-2)*(c-2)------------------ > c²+2c-5c-10=c²-4c+4
-3c-10=-4c+4----------------------------- > -3c+4c=4+10----------- > c=14
the solution is c=14
the domain of the function is (-∞,-2) U (-2,2) U (2,∞) or
<span>all real numbers except c=-2 and c=2</span>
Answer:
56
Step-by-step explanation:
Apply PEMDAS:
