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ludmilkaskok [199]
3 years ago
7

Convert to the given unit. 42 in. = ______ ft

Mathematics
2 answers:
maxonik [38]3 years ago
6 0

Answer:

  • There are 12 inches in a foot
  • 42/12(ft)

ValentinkaMS [17]3 years ago
3 0

Answer:

3.5

Step-by-step explanation:

42/12=3.5

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inna [77]
C-4>2c
minus c from both sides
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0-4>c
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c can be any number less than -4
3 0
4 years ago
PLEASE ANSWER THE QUESTION IN THE PICTURE BELOW
vekshin1

9514 1404 393

Answer:

  12 square inches

Step-by-step explanation:

The area is given by the formula ...

  A = 1/2bh

Here, the base is 6 inches and the height is given as 4 inches. Then the area is ...

  A = (1/2)(6 in)(4 in) = 12 in²

The area of the triangle is 12 square inches.

_____

<em>Comment on the problem</em>

Since you are given the base and height, we presume you are intended to use the formula above. You are also given all three side lengths. If you use the appropriate formula with those, you find the area is about 15.6 square inches. (The height of this triangle is actually closer to 5.2 inches.)

The figure represents a geometry that cannot exist. With the given base and height, the side lengths should be 5, not 6.

8 0
3 years ago
For f(x) = -5x + 4, what is the value of x for which f(x) = 20
Andru [333]

Answer:

- 3.2

Step-by-step explanation:

- 5x + 4 = 20

- 5x = 20 - 4

- 5x = 16

x = 16 / - 5

x = - 3.2

4 0
3 years ago
Assume a random sample of size n is from a normal population. Assume a single sample t test is used to for hypothesis testing. T
valentinak56 [21]

Answer:

True

Step-by-step explanation:

Type I and Type II are not independent of each other - as one increases, the other decreases.

However, increases in N cause both to decrease, since sampling error is reduced.

A small sample size might lead to frequent Type II errors, i.e. it could be that your (alternative) hypotheses are right, but because your sample is so small, you fail to reject the null even though you should.

5 0
3 years ago
Potatoes: Suppose the weights of Farmer Carl's potatoes are normally distributed with a mean of 9 ounces and a standard deviatio
katrin2010 [14]

Answer: a)  79.10 %           b) 7%                c)19.85 %

Step-by-step explanation:

a) Z = ( × - μ ) ÷ σ           Where  μ mean of population σ standard               deviation Z is the abscissa to give the area or probability we are looking for associated to the value 10 ounces ( × )

So:  Z = ( 10 - 9 ) ÷ 1.2  ⇒ Z = 1/1.2 ⇒   Z = 0.83  it has to be below this value

From Z tables we get  P [ Z ≤ 0.82 ] = 0.7910  0r  79.10 %

b) Following the same procedure: We look for

P [ Z > ( x - μ ) ÷   σ ]    ⇒   Z  =  ( 12 -10 ) ÷ 1.2  = 2.5

From Z table we get the area under the curve from the left tail up to the point Z < 2.5 ( 2.5 not included) but we were asked for the area out of that previous so 1- 0.9930 = 0.007 is the area we are looking for

So P (b) = 0.007  or 7 %

Finally between the two points above mentioned ( 10 ≤  Z  ≤ 12 ) we use the previous values (taking in consideration the limits, according to the problem statement )

Z ≤ 10     Z ⇒( 10-9  ) ÷ 1.2   Z = 0.7967

Z ≥ 12     Z ⇒ ( 12 - 9 ) ÷ 1.2  Z = 0.9952

The interval is between these two points

0.9952 - 0.7967 = 0.1985   ⇒ or 19.85 %

The attached help in the understanding of the solution

                               

5 0
3 years ago
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