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Zina [86]
2 years ago
10

WHATS 3 5/7+ 4 5/2??????//

Mathematics
2 answers:
mina [271]2 years ago
8 0

Answer:

55/2

(Decimal: 27.5)

Step-by-step explanation:

Debora [2.8K]2 years ago
4 0

Answer:

10.2142857143

Step-by-step explanation:

and huh?

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3.64 + 3/5 tell me the answer plz
kifflom [539]

Answer:

\huge\boxed{4.24}

Step-by-step explanation:

=> \sf 3.64+\frac{3}{5}                    [\sf \frac{3}{5} = 0.6]

=> 3.64 + 0.6

=> 4.24

Hope this helped!

~AnonymousHelper1807

6 0
3 years ago
If the Internet consisted of four computers, there would be six possible connections. If it consisted of five computers, there w
Luba_88 [7]

Answer:

<em>45 possible connections</em>

<em />

Step-by-step explanation:

The general equation for finding the possible number of connections in a network is given as

\frac{n*(n - 1)}{2}

where n is the number of computers on the network.

for 4 computers, we'll have

\frac{4*(4 - 1)}{2} = \frac{4*3}{2} = 6

for 5 computers, we'll have

\frac{5*(5 - 1)}{2} = \frac{5*4}{2} = 10.

therefore, for 10 computers, we will have

\frac{10*(10 - 1)}{2} = \frac{10*9}{2} = <em>45 possible connections</em>

3 0
3 years ago
Sketch the graph for each function. Choose either A, B, C, or D.
Serjik [45]
Hi. Here it is!
I hope this help...

—> And the answer is letter A

6 0
2 years ago
today's local newspaper lists 20 stocks of local interest. of those stocks ten increased five decreased and five remained unchan
coldgirl [10]

Answer:

P(x=2) = 0.2368

Step-by-step explanation:

given data

stocks of local interest N = 20

stocks increased K = 10

stocks decreased =  5

remained unchanged = 5

solution

we take here no of stock that are increased randomly n = 2

so here Hypergeometric random variable can take integer value

{max(0, n+k - N ), min(n,K) } = {0,2}

so here

P(x=2)

so

P(x=k)  = \frac{(^K_k)\times (^{N-K}_{n-k}) }{(^N_n)}      .......................1

P(x=2 ) = \frac{(^{10}_2)\times (^{20-10}_{2-2}) }{(^{20}_2)}    

solve it we get

P(x=2 ) = 0.236842

now we use excel function as

HYPGEOM.DIST (k,n,N.cumulative)   .....................2

so it will be

HYPGEOM.DIST (2,2,10,,false)

we get

HYPGEOM.DIST (2,2,10,,false)  = 0.236842

so

P(x=2) = 0.2368

4 0
3 years ago
Three kids play tennis at the same tennis courts. Mark plays every fourth day, David plays every seventh day and Bryan plays eve
jonny [76]

Answer:

Wednesday (9 weeks later) = 10th October.

Step-by-step explanation:

We label the days with the initials of the names.

M= 4

D = 7

B = 6

LCM of 6 +7 = 42

LCM of 6+7 + 4 = 84

We find 84 is the amount of days we need to add on to july 18th

We first find the weeks 84/7 = 9 weeks.

As Wednesday July 18th is exclusive it would be 84 days after this event.

18+ 84 = 102 days.

31 days in july = 31

31 days in Aug = 31

30 days in Sept = 30

= 92

102-92 = 10

We now know date is Wednesday 10th October

We can check 84 days = 9 weeks

13 days in July makes 31st july

31 days in Aug makes 31st Aug

30 days in Sept makes 30th Sept

= 74 days + 10 days = 84

10th October is the checked date and we know it is also a Wednesday as Wednesday had stayed exclusive and prove that there are 7 days in the week to account x 9, to account for an exact 9 weeks later duration.

6 0
3 years ago
Read 2 more answers
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