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SashulF [63]
2 years ago
13

May someone help me correct this if any corrections needed?

Spanish
1 answer:
Rudik [331]2 years ago
8 0

Here's link to the answer:

tinyurl.com/wpazsebu

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What is June 9,2020 in Spanish
timofeeve [1]

<em>_</em><em>_</em><em>_</em><em>_</em><em>_</em><em>_</em><em>_</em><em>_</em><em>_</em><em>_</em><em>_</em><em>_</em><em>_</em><em>_</em><em>_</em><em>_</em><em>_</em><em>_</em><em>_</em><em>_</em><em>_</em><em>_</em><em>_</em><em>_</em><em>_</em><em>_</em><em>_</em><em>_</em><em>_</em><em>_</em>

<em>Answer</em><em>:</em><em>. </em><em> </em><em>9</em><em> </em><em>De</em><em> </em><em>junio</em><em> </em><em>de</em><em> </em><em>2</em><em>0</em><em>2</em><em>0</em>

<em>hope</em><em> </em><em>it</em><em> </em><em>helps</em><em>.</em><em>.</em>

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3 years ago
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Fill in the blank with the indirect object pronoun Question 1
allsm [11]

Answer:

les gusta

Explanation:

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La presión del viento sobre las lonas de un
Anika [276]

Answer:

  • <u>11 mph</u>

Explanation:

Hola! Voy a responderte en el mismo idioma de tu pregunta.

Al establecer que<em> la presión del viento sobre las lonas de un velero varía  proporcionalmente con el área de las lonas y el cuadrado de la velocidad del viento</em>, puedes escribir una ecuación:

            p=kA\times v^2

Donde:

  • p es la presión del viento,
  • k es la constante de proporcionalidad,
  • A es el área de las lonas, y
  • v es la velocidad del viento.

Del hecho que<em> la presión sobre un pie cuadrado es de una libra cuando la velocidad es de 16 millas por hora</em>, puedes escribir:

  • 1 lb/pie² = k × 1 pie² × (16 mph)² ↔ ecuacion 1

<em>Calcula la velocidad del viento en millas por hora cuando la presión sobre una yarda cuadrada es de 36 libras. (1 yarda = 3 pies):</em>

  • p = 36 lb/yarda² × (1 yarda/3pie)² = 4 lb/pie²

  • A = 1yarda² × (3pie/yarda)² = 9 pie²

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Divide la ecuación 2 por la ecuación 1, para eliminar la constante, k:

        \dfrac{4lb/pie^2}{1lb/pie^2}=\dfrac{9pie^2\times v^2}{1pie^2\times (16mph)^2}

       v^2=4\times (16mph)^2/9\\\\v=2\times 16mph/3\\\\v\approx10.7mph\approx11mph\longleftarrow answer

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