the height of the tree is 23 feet .
<u>Step-by-step explanation:</u>
Here we have , Tony is 5.75 feet tall. Late one afternoon, his shadow was 8 feet long. At the same time, the shadow of a nearby tree was 32 feet long. We need to find Find the height of the tree. Let's find out:
According to question , Tony is 5.75 feet tall. Late one afternoon, his shadow was 8 feet long . Let the angle made between Tony height and his shadow be x . Now , At the same time, the shadow of a nearby tree was 32 feet long. Since the tree is nearby so tree will subtend equal angle of x. Let height of tree be y , So
⇒ 
But , From tony scenario
⇒ 
Equating both we get :
⇒ 
⇒ 
⇒ 
Therefore , the height of the tree is 23 feet .
Answer:
? = 13.6
Step-by-step explanation:
the angle between a tangent and the diameter = 90°
Then the triangle is right with legs 2 × 6 = 12 and 6.4
using Pythagoras' identity in the right triangle.
the square on the hypotenuse is equal to the sum of the squares on the legs , that is
? ² = 12² + 6.4² = 144 + 40.96 = 184.96 ( take square root of both sides )
? = 
= 13.6
Answer: Henry read for a total of 40 minutes
Step-by-step explanation: 3:00 - 0:50 is 2:10 then 2:10 - 1:30= 40 minutes
Factor out the GCF of
21
b
2
c
2
from
63
b
2
c
4
+
42
b
3
c
2
.
Tap for fewer steps...
Factor out the GCF of
21
b
2
c
2
from each term in the polynomial.
Tap for fewer steps...
Factor out the GCF of
21
b
2
c
2
from the expression
63
b
2
c
4
.
21
b
2
c
2
(
3
c
2
)
+
42
b
3
c
2
Factor out the GCF of
21
b
2
c
2
from the expression
42
b
3
c
2
.
21
b
2
c
2
(
3
c
2
)
+
21
b
2
c
2
(
2
b
)
Since all the terms share a common factor of
21
b
2
c
2
, it can be factored out of each term.
21
b
2
c
2
(
3
c
2
+
2
b
)
The greatest common factor
GCF
is the term in front of the factored expression.
21
b
2
c
2
