Given F(X)= 3x(exponent 4) -14x(exponent 3) +18x+23
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The point of intersection you are concerned with is the left-most of those of the graphed lines. Thus you want the two equatons that both have x-intercepts that are negative. Since the x-coefficient is positive in every case, this will mean the right-side constants of these equations both need to be negative. The appropriate choice is ...
A. 4x - 5y = -5 and 3x + 10y = -20
A. 4x - 5y = -5 and 3x + 10y = -20