3 years ago

What is the HCF of 27 and 15

Mathematics

2 answers:

Deffense [45]3 years ago

4 0

Answer: 3

Step-by-step explanation:

5x3=15 and 3x9=27 so it’s 3.

GrogVix [38]3 years ago

3 0

Answer:

Step-by-step explanation:

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(5a+2)(a+4)=<br> this is supposed to be a polynomial in standard form

Shkiper50 [21]

Answer:

5a²+22a+8

Step-by-step explanation:

(5a×a)+(5a×4)+(2×a)+(2×4)

=5a²+20a+2a+8

=5a²+22a+8

7 0

3 years ago

Can someone explain this to me:)

Ostrovityanka [42]

Answer:

B) m = 2 , b = -3

Step-by-step explanation:

b = y-intercept

The y-intercept is -3

b = -3

m = slope

The slope is 2

m = 2

7 0

3 years ago

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marshall27 [118]

Answer:

the last one

Step-by-step explanation:

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3 years ago

If f(x)=4x^2+1 and g(x) = x^2-5 fins (f-g)(x)

arlik [135]

Answer:

Given:

f(x) = 4x² + 1

g(x) = x² - 5

Then

(f + g)(x) = 4x² + 1 + x² - 5

= 5x² - 4

Answer: 5x² - 4

5 0

4 years ago

Log(x⁴+3x³) - log(X + 3 ) + log2 - log6 = 2logx . find the value of x

AfilCa [17]

The given equation is

$\begin{gathered} \log (x^4+3x^3)-\log (x+3)+\log 2-\log 6=2\log x \\ \log (\frac{x^4+3x^{3^{}}}{x+3})+\log \frac{2}{6}=\log x^2 \\ \log \frac{x^3(x+3)}{x+3}+\log \frac{1}{3}=\log x^2 \\ \log x^3+\log \frac{1}{3}=\log x^2 \\ \log \frac{x^3}{3}=\log x^2 \\ \frac{x^3}{3}=x^2 \\ x^3-3x^2=0 \\ x^2(x-3)=0 \end{gathered}$

hence

$x=0\text{ or x=3}$

But x cannot be zero so x=3

So the value of x is 3

7 0

1 year ago