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malfutka [58]
2 years ago
13

Decide if it is always true or never true

Mathematics
2 answers:
MaRussiya [10]2 years ago
4 0

Answer:

1. 8

2. -3

3. -15 or -10

Step-by-step explanation:

sashaice [31]2 years ago
3 0

Answer:

Q1.Let's solve your equation step-by-step.

2(x+3)=5x+6−3x

Step 1: Simplify both sides of the equation.

2(x+3)=5x+6−3x

(2)(x)+(2)(3)=5x+6+−3x(Distribute)

2x+6=5x+6+−3x

2x+6=(5x+−3x)+(6)(Combine Like Terms)

2x+6=2x+6

2x+6=2x+6

Step 2: Subtract 2x from both sides.

2x+6−2x=2x+6−2x

6=6

Step 3: Subtract 6 from both sides.

6−6=6−6

0=0

Answer:

All real numbers are solutions.

Q2.x−3=2x−3−x

Step 1: Simplify both sides of the equation.

x−3=2x−3−x

x+−3=2x+−3+−x

x−3=(2x+−x)+(−3)(Combine Like Terms)

x−3=x+−3

x−3=x−3

Step 2: Subtract x from both sides.

x−3−x=x−3−x

−3=−3

Step 3: Add 3 to both sides.

−3+3=−3+3

0=0

Answer:

All real numbers are solutions.

Q3.3(x−5)=2(x−5)+x

Answer:

There are no solutions.

Step-by-step explanation:

Hope I helped

Brainliest plz

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4 = -8Z - 7 + 8z<br> Giving the brainliest to whoever gets the right answer.
liubo4ka [24]

Answer:

No Solution

Step-by-step explanation:

if one side is 4, another side -8z and +8z cancels, left -7

4 ≠ -7

8 0
3 years ago
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How many different linear arrangements are there of the letters a, b,c, d, e for which: (a a is last in line? (b a is before d?
inna [77]
A) Since a is last in line, we can disregard a, and concentrate on the remaining letters.
Let's start by drawing out a representation:

_ _ _ _ a

Since the other letters don't matter, then the number of ways simply becomes 4! = 24 ways

b) Since a is before d, we need to account for all of the possible cases.

Case 1: a d _ _ _ 
Case 2: a _ d _ _
Case 3: a _ _ d _
Case 4: a _ _ _ d

Let's start with case 1.
Since there are four different arrangements they can make, we also need to account for the remaining 4 letters.
\text{Case 1: } 4 \cdot 4!

Now, for case 2:
Let's group the three terms together. They can appear in: 3 spaces.
\text{Case 2: } 3 \cdot 4!

Case 3:
Exactly, the same process. Account for how many times this can happen, and multiply by 4!, since there are no specifics for the remaining letters.
\text{Case 3: } 2 \cdot 4!

\text{Case 4: } 1 \cdot 4!

\text{Total arrangements}: 4 \cdot 4! + 3 \cdot 4! + 2 \cdot 4! + 1 \cdot 4! = 240

c) Let's start by dealing with the restrictions.
By visually representing it, then we can see some obvious patterns.

a b c _ _

We know that this isn't the only arrangement that they can make.
From the previous question, we know that they can also sit in these positions:

_ a b c _
_ _ a b c

So, we have three possible arrangements. Now, we can say:
a c b _ _ or c a b _ _
and they are together.

In fact, they can swap in 3! ways. Thus, we need to account for these extra 3! and 2! (since the d and e can swap as well).

\text{Total arrangements: } 3 \cdot 3! \cdot 2! = 36
7 0
2 years ago
PLEASE HELP I WILL GOVE BRAINIEST
Elza [17]

Answer: the answer is x<-4 so the correct answer choice would be D

Step-by-step explanation: Hope this helps :)

7 0
2 years ago
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Find the gradient and y intercept of 3x+4y=5
noname [10]

Answer:

gradient = - \frac{3}{4} , y- intercept = \frac{5}{4}

Step-by-step explanation:

The equation of a line in slope- intercept form is

y = mx + c ( m is the slope and c the y- intercept )

Given

3x + 4y = 5 ( subtract 3x from both sides )

4y = - 3x + 5 ( divide terms by 4 )

y = - \frac{3}{4} x + \frac{5}{4} ← in slope- intercept form

with slope m = - \frac{3}{4} and y- intercept c = \frac{5}{4}

3 0
3 years ago
Linda's grandmother baked brownies on Saturday for her church's bake sale. She cut each batch of brownies into 9 large pieces. S
LiRa [457]

Answer:

C - 8

Step-by-step explanation:

153 - 81 = 72

72 ÷ 9 = 8

5 0
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