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vivado [14]
3 years ago
10

during a test of a totalizing flow meter, the water depth rose 15 inches in a tank 18 inches in diameter. What was the total flo

w in gallons
Mathematics
1 answer:
sattari [20]3 years ago
4 0

Answer:

The total flow in gallons is approximately 16.524 gallons

Step-by-step explanation:

The given diameter of the tank, D = 18 inches

The amount by which the water depth rose, Δh = 15 inches

The quantity being measured = The total flow = The change in volume of water in the tank

The change in the volume of the water in the tank, ΔV = (π × D²/4) × Δh

Substituting the known values, gives;

ΔV = (π × D²/4) × Δh = (π × (18 in.)²/4) × (15 in.) ≈ 3817.035 in.³

1 gallon = 231 in.³

ΔV ≈ 3817.035 in.³ = 3817.035 in.³ × 1 gallon/(231 in.³)  ≈ 16.524 gallons

The change in the volume of the water in the tank, ΔV in gallons = The total flow in gallons ≈ 16.524 gallons.

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the city of James town is 2 meters below sea level. Takoradi, a city in western region, is 7 meters below sea level . How much h
never [62]

Answer:

James town is 5 meters higher than Takoradi​ .

Step-by-step explanation:

Given:

Height of James town = 2 meters below sea level

Height of Takoradi town = 7 meters below sea level

To find:

How much higher is James town that Takoradi = ?

Solution:

As we can see the standard of height is how much the town is below the sea level.

So, the height of town having lesser value will be at a higher level.

Value of Height of James town is lesser than that of Takoradi town.

Therefore, James town is at a higher level.

Difference of height = 7 meters - 2 meters = 5 meters

So, the answer is:

James town is 5 meters higher than Takoradi.

8 0
3 years ago
(1.1/1.2: Interpolating polynomials) Say we want to find a polynomialf(x) ofdegree 3,f(x) =a0+a1x+a2x2+a3x3,satisfying some inte
Hunter-Best [27]

(a) If

<em>f(x)</em> = <em>a</em>₀ + <em>a</em>₁ <em>x </em>+<em> a</em>₂ <em>x</em> ² + <em>a</em>₃ <em>x</em> ³

then from the given conditions we get the system of equations,

<em>f</em> (-1) = <em>a</em>₀ - <em>a</em>₁<em> </em>+<em> a</em>₂ - <em>a</em>₃ = -1

<em>f</em> (1) = <em>a</em>₀ + <em>a</em>₁<em> </em>+<em> a</em>₂ + <em>a</em>₃ = 2

<em>f</em> (2) = <em>a</em>₀ + 2<em>a</em>₁<em> </em>+ 4<em>a</em>₂ + 8<em>a</em>₃ = 1

<em>f</em> (3) = <em>a</em>₀ + 3<em>a</em>₁<em> </em>+<em> </em>9<em>a</em>₂ + 27<em>x</em> ³ = 5

(b) Similarly, if

<em>f(x)</em> = <em>a</em>₀ + <em>a</em>₁ <em>x </em>+<em> a</em>₂ <em>x</em> ² + <em>a</em>₃ <em>x</em> ³

then

<em>f'(x)</em> = <em>a</em>₁<em> </em>+<em> </em>2<em>a</em>₂ <em>x</em> + 3<em>a</em>₃ <em>x</em> ²

so that the given conditions yield the system,

<em>f</em> (1) = <em>a</em>₀ + <em>a</em>₁<em> </em>+<em> a</em>₂ + <em>a</em>₃ = 0

<em>f'</em> (1) = <em>a</em>₁<em> </em>+<em> </em>2<em>a</em>₂ + 3<em>a</em>₃ = 2

<em>f</em> (2) = <em>a</em>₀ + 2<em>a</em>₁<em> </em>+<em> </em>4<em>a</em>₂ + 27<em>a</em>₃ = 3

<em>f'</em> (2) = <em>a</em>₁<em> </em>+<em> </em>4<em>a</em>₂ + 12<em>a</em>₃ = -1

7 0
3 years ago
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Lerok [7]

i just want tp know what app this is or what yall are learning over here

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A cell phone weighs about 2.8x 10pounds. Which value of n is most reasonable?
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Given the data below:
Leno4ka [110]

Answer:

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Since after x=3, value of y starts decreasing for increasing values of x, let's choose. Also we need to find f(x) for x=3.4

x=3,4,5 and f(x)=7,3,1 to find lagrange polynomial

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P(3.4)= 5.16

7 0
3 years ago
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