Answer:
x = 1 and y = 4
Step-by-step explanation:
m² = 7x + 7; m³= 4y and m∧4 = 112
√(m∧4) = √112
∴ m² = √112
Hence, 7x + 7 = √112
(7x + 7)² = 112
49x² + 14x + 49 = 112
49x² + 14x - 63 = 0
7x² + 2x - 9 = 0
7x² + 9x - 7x - 9 = 0
x(7x + 9) - 1(7x + 9) = 0
(x - 1)(7x + 9) = 0
x - 1 = 0
∴ x = 1
When x = 1
m²= 7 + 7 = 14
m³= 4y and m∧4 = 112
Also m∧4/m²= m² = 112/14 = 8
Hence, m° = 2; m = 2 X 2 = 4; m² = 2 x 2 x 2 = 8; m³= 2 x 2 x2 x 2 = 16
m³ = 16 = 4y
∴ y = 16/4 = 4
Answer:
I think it's 30
Step-by-step explanation:
I took it as reflection of light..or ig it has same idea
It’s C. X+5
Hope this Helps!
Correct me if I’m wrong!
Answer:
-8x + y = -32
Step-by-step explanation:
Where's the variable x? I will assume you meant -32x + 4y = 4.
Any line parallel to this given line has an equation of the same form but a different constant:
Substituting the coordinates (4, 0) into -32(4) + 4(0) = C, we get:
-128 + 0 + C, and so C = -128, and:
the desired equation is -32x + 4y = -128
or, after reduction, -16x + 2y = -64, or -8x + y = -32