Let’s call the speed of the slower car S, then the speed of the other is S+10mph.
At 5pm they have been travelling for 3 hours. The slower car travels a distance 3S and the faster one 3(S+10).
But the two distances must add up to 240 miles so 3S+3(S+10)=240, 3S+3S+30=240, 6S=210, S=35 mph. The faster car’s speed is 45mph. We can see that 3S is the same distance as 3x, so x=S=35 mph, and the distance the faster car travels is 3×45=135 miles.
722 bricks and 8 workers.
Answer:
the pre-image and the image are congruent
Step-by-step explanation:
Alright, lets get started.
Suppose first mechanic charges= x
So, second mechanic charges will be =
(because total of their rates was 125)
first mechanic worked for 5 hours, and the second mechanic worked for 15 hours and together they charged a total of $1225
Means



Adding 10 x in both sides

Subtracting 1225 from both sides

Dividing 10 in both sides

x = 65
For second mecahnics rate = 125 - 65 = 60
Hence The mechanic who worked 5 hours charged $ 65 per hour, the one who worked 15 hours charged $ 60 per hour: Answer
Hope it will help :)