Help with this I gave all my points plzzz
1 answer:
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Answer:
10. ○
9. ○680%
8. ○40%
7. ○
6. ○0,4, 40,5%, 11⁄25, 4⁄9
5. ○
4. ○1%
3. ○76%
2.
1.
Step-by-step explanation:
10. To convert from a percentage to a decimal, move the decimal mark twice to the left; each 20 is worth 5, and since 5 by 17 is 85, you have your fractional part of 17⁄20, then attach the whole number of 4.
9. To convert from a mixed number\improper fraction to a percentage, first evaluate the fractional part for a decimal answer, then move the decimal mark twice to the <em>right</em>.
8. To convert from a fraction to a percentage, evaluate the fraction for a decimal answer, then move the decimal mark twice to the right.
7. 60%
Greatest Common Divisor [GCD]: 44
6. 44%
_
44,4%
40%
Now that these are all percentages, it is alot easier to order them from least to greatest.
5. To convert from a percentage to a decimal, move the decimal mark twice to the <em>left</em>.
4. To convert from a decimal to a percentage, move the decimal mark twice to the <em>right</em>.
3. Each 25 is worth 4, and since 4 by 19 is 76, you get 76%.
2. Each 25 is worth 4, and since 4 by 6 is 24, you get 24%, and this graph.
1. Each 36 is worth 2 7⁄9, and since 12 by 2 7⁄9 is 33⅓, you get 33⅓%, so you would choose this answer.
I am joyous to assist you anytime.
Given that 
, then 
The slope of a tangent line in the polar coordinate is given by:
Thus, we have:
Part A:
For horizontal tangent lines, m = 0.
Thus, we have:
Therefore, the <span>values of θ on the polar curve r = θ, with 0 ≤ θ ≤ 2π, such that the tangent lines are horizontal are:
</span><span>θ = 0
</span>θ = <span>2.02875783811043
</span>
θ = <span>4.91318043943488
Part B:
For vertical tangent lines,
Thus, we have:
</span>Therefore, the <span>values of θ on the polar curve r = θ, with 0 ≤ θ ≤ 2π, such that the tangent lines are vertical are:
</span>θ = <span>4.91718592528713</span>
The slope of a tangent line in the polar coordinate is given by:
Thus, we have:
Part A:
For horizontal tangent lines, m = 0.
Thus, we have:
Therefore, the <span>values of θ on the polar curve r = θ, with 0 ≤ θ ≤ 2π, such that the tangent lines are horizontal are:
</span><span>θ = 0
</span>θ = <span>2.02875783811043
</span>
θ = <span>4.91318043943488
Part B:
For vertical tangent lines,
Thus, we have:
</span>Therefore, the <span>values of θ on the polar curve r = θ, with 0 ≤ θ ≤ 2π, such that the tangent lines are vertical are:
</span>θ = <span>4.91718592528713</span>