Answer:
27.0 feet
Step-by-step explanation:
Length of an arc (s) = 2πrθ/360................. Equation 1
Where r = radius of the circle, θ = angle in degree substends by the arc at the center of the circle.
From the question,
Given: r = 9 feet, θ = 3 radian = 3 (57.2950) = 171.89°
Constant: π = 3.14
Substitute these values into equation 1
s = 2(3.14)(9)(171.89)/360
s = 9715.2228/360
s = 26.99 feet
s ≈ 27.0 feet
198 is the answer ok ok ok
Answer: The probability of drawing 5 cards in either ascending or descending order out of the deck of 52 standard playing cards is 0.84%.
Step-by-step explanation: We have the following cards in a deck: 1(ace), 2, 3, 4, 5, 6, 7, 8, 9, 10, 12(Jack), 13(Queen), 14(King) (thirteen different in total). There are 4 copies of each of them yielding 52 cards in total. First to draw all of the cards in the ascending order all of the drawn cards need to be different. Imagine you have 13 piles of 4 identical cards. Let us calculate the number of ways you can select 5 different ones (the order matters). First you select 5 different piles (this secures that each card is different) and this is possible to do in 
(we use the formula for variations since the order matters). Now, each card in the pile can be selected in 
different ways so the total number of sequences with 
different cards is 
. Now we select out of these sequences the clases of those that contain exactly the same cards but in different order. Only 4 of the sequences within the same class will be in ascending order out of 4*5! which is the total number of the sequences within the class! This means that we have to multiply our total number of sequences of 5 different cards by 
and this yields the final answer of total number of ascending sequences to be
The total number of possible ways to draw 5 out of 52 cards is just
This yields for the probability
Exactly the same calculation applies for the descending order. So the probabilty of the cards being in either ascending or descending order is just the sum of these two (the events are mutually exclusive, you cannot have both the ascending and descending order at the same time) yielding the final probability of 
.
This might help you..need more information
This type of combination problem involves combined probability, or the chance that a specific set could be chosen based on the probability of multiple variables.
The number that could be generated follows the example:
XXYZZZZ
where X describes a letter, and Y describes a number that isn’t zero, and Z describes any number.
Two probabilities exist in this situation, depending on the circumstances of the question. By pressing any number once, only 8 letters can be used (ten digits, minus the one and two keys, since they don’t have letters). This means that the probability of this event is:
8 x 8 x 9 x 10 x 10 x 10 x 10
where the two eights are for the letters, the nine is for the digit that isn’t zero, and the tens are for any numbers from the keypad. This permutation yields 5,760,000 choices.
If you are allowed to press the numbers more than once to generate a letter, then the probability changes to account for the entire alphabet. The new probability of this event is :
26 x 26 x 9 x 10 x 10 x 10 x 10
where this permutation yields 60,840,000 choices.
Hope this helps!
