These dot plots show the ages (in years) for a sample of two types of fish.
1 answer:
*Select two choices: one for the centers and one for the spreads.
A. Centers: The sharks have a lower median age than the koi
B. Spreads: The ages of the koi are more spread out.
C. Centers: The sharks have a greater median age than the koi.
D. Spreads: The ages of the sharks are more spread out
(See attachement for diagram)
Answer:
A. and B.
Step-by-step explanation:
Measure of center that can be used in stating the differences between Koi and Shark is the median.
Examining the dot plot, the median age for Sharks is 20.
The median age for Koi is the 14th data point, which is 40.
Thus, for the center, we can conclude that Sharks has a lower median age than Koi.
For the spread, the larger the range, the more spread out the data are.
Thus:
Range for Sharks = 30 - 10 = 20
Range for Koi = 70 - 25 = 45
Therefore, we can conclude that the ages of Koi are more spread out.
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Answer:
(2;-5) and (0;-4).
Step-by-step explanation:
if the given graph is the same as in the attached picture (y=-0.5x-4), then two points only belong to it.
<h3>Answer: y = 3x+4</h3>
Slope = 3
y intercept = 4
========================================================
Explanation:
Let's find the slope.
The slope is m = 3.
The y intercept is b = 4 due to the point (0,4). The y intercept <u>always</u> occurs when x = 0.
We'll then plug those m and b values into y = mx+b to get the answer y = 3x+4
-----------
As a way to check the answer, plugging x = 0 should lead to y = 4
y = 3x+4
y = 3*0+4
y = 0+4
y = 4
So that works out. Let's try x = 1. It should produce y = 7
y = 3x+4
y = 3*1+4
y = 3+4
y = 7
That works out also. The answer is fully confirmed.