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ANTONII [103]
3 years ago
6

Students have

SAT
2 answers:
dusya [7]3 years ago
5 0

Answer:

A. 30 minutes I'm pretty sure

Vedmedyk [2.9K]3 years ago
5 0
A. 30 minutes
“ACT Aspire writing assessments consist of 30-minute summative writing tasks for grades 3 through 8 and early high school. They ask students at each grade level to respond in essay form to a single writing stimulus.”
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Summarize the work of famous environmental scientists of the past.
dlinn [17]

thomas edison was a good one or professor edison if you may

6 0
3 years ago
9 x 20= Puntos libres
Gemiola [76]

Answer:

180

Explanation:

because you have to multiply 9 x 20 which gives you 180 for your total

5 0
3 years ago
Read 2 more answers
This section consists of NINE (18) multiple-choice questions. Each question is worth one (1) mark. Read the below case study and
devlian [24]

In light of this fact, it is best if the firm adjusts its hurdle rate (i.e., cost of capital) upward to compensate for this fact.

<h3>What is hurdle rate?</h3>

A hurdle rate is known to be the lowest  rate of return that is needed on a project or any kind of investment.

Note that Some projects do take an undoubtedly result in zero and as such,  In light of this fact, it is best if the firm adjusts its hurdle rate (i.e., cost of capital) upward to compensate for this fact.

Learn more about hurdle rate  from

brainly.com/question/14285844

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3 0
2 years ago
how many milliliters of 0.200 m nh₄oh are needed to react with 12.0 ml of 0.550 m fecl₃? fecl₃+ 3nh₄oh → fe(oh)₃ + 3nh₄cl
siniylev [52]

You're starting with

(12.0 mL) (0.550 M) = (0.0120 L) (0.550 M) = 0.00660 mol

of FeCl₃.

For every mole of FeCl₃ in the balanced reaction, you need 3 moles of NH₄OH, so you need a minimum 0.0198 mol NH₄OH per mole FeCl₃.

Then the requisite volume of NH₄OH solution needed is <em>V</em> such that

(0.0198 mol) / <em>V</em> = 0.200 M

Solve for <em>V</em> to get

<em>V</em> = (0.0198 mol) / (0.200 M) = 0.0990 L = 99 mL

5 0
3 years ago
What units are used when describing the length of time that the universe has been expanding?
Dmitriy789 [7]

Answer:

kilometers/second per million parsecs

Explanation:

It is sometimes called Hubble time

It is what astronomers use for the Hubble constant

3 0
3 years ago
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