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Aleks [24]
3 years ago
11

I'll mark brainliest,,plz helpp!!

Mathematics
2 answers:
V125BC [204]3 years ago
7 0
All real numbers fjaksjdnbsak
viktelen [127]3 years ago
4 0
I’m pretty sure it’s no solution tell me if I’m wrong
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Can y’all help me? i’ll literally fail if i don’t get these right lol
ioda

Answer:

63 degrees.

Step-by-step explanation:

TRaingle ABC is isosceles so the base angles are equal That is < BAC = < BCA.

<BAC = 180 - 117 = 63 degrees ( because it  is adjacent to <x which is 63 degrees).

So < BCA = <BAC = 63 degrees.

Finally y = 63 degrees ( vertical angles are equal).

5 0
3 years ago
Find the area and the circumference of a circle with radius 3 m. Use the value 3.14 for π, and do not round your answers. Be sur
Gennadij [26K]

Circumference: 18.84 m

Area: 28.26m^{2}

Explanation

For circumference, use the formula \pi*d, where d=the diameter(the radius times 2).

For area, use the formula \pir^{2}, where r=the radius. Make sure to square the radius first before multiplying by pi!

A good way to remember these formulas is Cherry(circumference) Pi(\pi) is Delicious(diameter) and Apple(area) \pi r^{2}("are too")

8 0
3 years ago
Find the distance between these points. C(0, 4), T(-6, -3) √(37) √(109) √(85)
finlep [7]

Answer:

The answer is

<h2>\sqrt{85}</h2>

Step-by-step explanation:

The distance between two points can be found by using the formula

<h3>d =  \sqrt{( {x1 - x2})^{2}  +  ({y1 - y2})^{2} }  \\</h3>

where

(x1 , y1) and (x2 , y2) are the points

From the question the points are

C(0, 4), T(-6, -3)

The distance between them is

<h3>|CT|  =  \sqrt{ ({0 + 6})^{2}  +  ({4 + 3})^{2} }  \\  =  \sqrt{ {6}^{2} +  {7}^{2}  }  \\  =  \sqrt{36 + 49}</h3>

We have the final answer as

<h3>\sqrt{85}</h3>

Hope this helps you

6 0
3 years ago
3. Rectangle ABCD is shown on the coordinate grid below.
VMariaS [17]

Answer:

A. 8 units

Step-by-step explanation:

Coordinates of A = (-2, -2)

Coordinates of C = (5, 2)

Use distance formula, d = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2} to calculate the length of diagonal \overline{AC}.

Let,

A(-2, -2) = (x_1, y_1)

C(5, 2) = (x_2, y_2)

d = \sqrt{(5 -(-2))^2 + (2 -(-2))^2}

d = \sqrt{(7)^2 + (4)^2}

d = \sqrt{49 + 16} = \sqrt{65}

d = 8.1 (nearest tenth)

Therefore, the closest to the length of diagonal \overline{AC} = 8 units

4 0
3 years ago
I dont know how to do this pls help ​
Alecsey [184]

Answer:

1) 225

2) 2304

Step-by-step explanation:

1)

Use geometric mean of legs

x = \sqrt{(16+9)^2 * 9^2} = \sqrt{25^2 * 9^2}  = 25 * 9 = 225

2)

Use geometric mean of altitude

x = \sqrt{(100-36)^2 * 36^2} = \sqrt{64^2 * 36^2} = 64 * 36 = 2304

5 0
3 years ago
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