Let the mass of the object exists at 60 N and the height exists at 3m then work
exists in 1764.
What is work?
The work done by a force exists determined to be the product of a component of the force in the direction of the displacement and the magnitude of this displacement.
Work can be estimated by multiplying Force and Distance in the direction of force as follows.
W = F × d. Unit.
Given data:
m = mass of the object = 60 N
h = height = 3 m
Work = Fh = mgh
g = gravity = 9.8 m/s²
work = Fh = mgh
= 1764
Therefore, the work exists in 1764.
To learn more about work refer to:
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Answer:
Step 3
Step-by-step explanation:
She made her first mistake in Step 3.
This is because 4/7 is actually less than 5/3.
Step 1 and 2 are mathematically accurate.
1/2 is less than 1.
So, since 4/7 is only greater than 1/2 and not greater than 1 as compared to 5/3 which is actually greater than 1, she should have concluded that 4/7 is less than 5/3.
Therefore, Step 3 contains the mistake.
These are the y intercepts
1. (0, 1/3)
2. (0, 26/3)
Answer:
For this case we know that the confidence level is 90% so then the significance level is 
and 
. And we can find in the normal standard distribution a value who accumulates 0.5 of the area on each tail and we got:
And the best option would be:
1.645
Step-by-step explanation:
We assume that the parameter of interest is 
and we can assume that the distribution for this parameter is normally distributed so then the confidence interval assuming a two sided interval is given by:
Where 
represent the estimator for the parameter, SE the standard error and 
the critical value.
For this case we know that the confidence level is 90% so then the significance level is and . And we can find in the normal standard distribution a value who accumulates 0.5 of the area on each tail and we got:
And the best option would be:
1.645
The answer is 21x-28 hope it helps
