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ivanzaharov [21]
3 years ago
9

A hyperbola is the set of all points in a plane such that the absolute value of the difference of the distances from two fixed p

oints, called the foci, is constant.
Please select the best answer from the choices provided

A. True
B. False
Mathematics
1 answer:
Anna35 [415]3 years ago
3 0
The answer is true, by definition, its true.
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For every 12 students that wore sneakers, there were 9 students that wore boots. How many students wore sneakers if 24 students
Olenka [21]

Answer:

C (32)

Step-by-step explanation:

12 sneakers / 9 boots = x sneakers / 24 boots

the ratio is 4:3 so divide 24 by 3 and multiply by 4

12 / 9 = (24 / 3 x 4) / 24

12 / 9 = 32 / 24

32 students wore sneakers

7 0
3 years ago
Read 2 more answers
A rope is 72 feet long. What is the length of the rope in yards
Lostsunrise [7]
The answer would be 24 yards. This would be 24 because 3 feet equal one yard so 3/72 is 24 or 24•3.
6 0
4 years ago
a shop sell 200 chocolate ; vanilla and strawberry ice cream 45% of the ice cream sold are vanilla and 35% are strawberry. how m
Oksanka [162]

The number of chocolate ice creams sold is 50.

<h3>How many chocolate ice creams are sold?​</h3>

There exist three kinds of flavors.

45% of the ice creams exist as vanilla

30% of the ice creams exist as strawberry

x percent of the ice creams exist chocolate

The total amount of ice cream exists 200 which equals 100%.

Therefore,

45% + 30% + x = 100%

To estimate the value of x, bring the variable to the left side and bring all the remaining values to the right side. Simplify the values to estimate the result.

Solving for x, then the value of x is,

x = 25%

Then the number of chocolate ice creams are:

25%(200) = 50.

The number of chocolate ice creams sold is 50.

To learn more about the value of x refer to:

brainly.com/question/9965443

#SPJ2

6 0
2 years ago
HELP HURRY PLEASE i dont understanddd
BigorU [14]

Answer:

see image

Step-by-step explanation:

put a point on .5 on the x axis and a point on -3 on the y axis draw a line through them and shade the space under the line

6 0
3 years ago
Lie detectors have a 15% chance of concluding that a person is lying even when they are telling the truth. a bank conducts inter
Otrada [13]
Part A:

Given that lie <span>detectors have a 15% chance of concluding that a person is lying even when they are telling the truth. Thus, lie detectors have a 85% chance of concluding that a person is telling the truth when they are indeed telling the truth.

The case that the lie detector correctly determined that a selected person is saying the truth has a probability of 0.85
Thus p = 0.85

Thus, the probability that </span>the lie detector will conclude that all 15 are telling the truth if <span>all 15 applicants tell the truth is given by:

</span>P(X)={ ^nC_xp^xq^{n-x}} \\  \\ \Rightarrow P(15)={ ^{15}C_{15}(0.85)^{15}(0.15)^0} \\  \\ =1\times0.0874\times1=0.0874
<span>

</span>Part B:

Given that lie detectors have a 15% chance of concluding that a person is lying even when they are telling the truth. Thus, lie detectors have a 85% chance of concluding that a person is telling the truth when they are indeed telling the truth.

The case that the lie detector wrongly determined that a selected person is lying when the person is actually saying the truth has a probability of 0.25
Thus p = 0.15

Thus, the probability that the lie detector will conclude that at least 1 is lying if all 15 applicants tell the truth is given by:

P(X)={ ^nC_xp^xq^{n-x}} \\ \\ \Rightarrow P(X\geq1)=1-P(0) \\  \\ =1-{ ^{15}C_0(0.15)^0(0.85)^{15}} \\ \\ =1-1\times1\times0.0874=1-0.0874 \\  \\ =0.9126


Part C:

Given that lie detectors have a 15% chance of concluding that a person is lying even when they are telling the truth. Thus, lie detectors have a 85% chance of concluding that a person is telling the truth when they are indeed telling the truth.

The case that the lie detector wrongly determined that a selected person is lying when the person is actually saying the truth has a probability of 0.15
Thus p = 0.15

The mean is given by:

\mu=npq \\  \\ =15\times0.15\times0.85 \\  \\ =1.9125


Part D:

Given that lie detectors have a 15% chance of concluding that a person is lying even when they are telling the truth. Thus, lie detectors have a 85% chance of concluding that a person is telling the truth when they are indeed telling the truth.

The case that the lie detector wrongly determined that a selected person is lying when the person is actually saying the truth has a probability of 0.15
Thus p = 0.15

The <span>probability that the number of truthful applicants classified as liars is greater than the mean is given by:

</span>P(X\ \textgreater \ \mu)=P(X\ \textgreater \ 1.9125) \\  \\ 1-[P(0)+P(1)]
<span>
</span>P(1)={ ^{15}C_1(0.15)^1(0.85)^{14}} \\  \\ =15\times0.15\times0.1028=0.2312<span>
</span>
8 0
4 years ago
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