Question

In quadrilateral ABCD, angle BAD and angle CDA are trisected as shown. What is the degree measure of angle AFD?

Answer 1

Answer: AFD = 80

Explanation:

110 + 100 + 3x + 3y = 360
210 + 3x + 3y = 360
3x + 3y = 150
3(x + y) = 150
x + y = 50

Now look at polygon ABCDF (5 sided polygon)

100 + 110 + x + y + Angle F = 540
210 + 50 + angle F = 540
260 + angle F = 540
Angle F = 280

And:
angle F + AFD = 360 degree
280 + AFD = 360
AFD = 80