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umka21 [38]
4 years ago
9

In quadrilateral ABCD, angle BAD and angle CDA are trisected as shown. What is the degree measure of angle AFD?

Mathematics
1 answer:
djverab [1.8K]4 years ago
4 0
Answer: AFD = 80

Explanation:

110 + 100 + 3x + 3y = 360
210 + 3x + 3y = 360
3x + 3y = 150
3(x + y) = 150
x + y = 50

Now look at polygon ABCDF (5 sided polygon)

100 + 110 + x + y + Angle F = 540
210 + 50 + angle F = 540
260 + angle F = 540
Angle F = 280

And:
angle F + AFD = 360 degree
280 + AFD = 360
AFD = 80
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\boxed{\bold{x \ = \ -2}}

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