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lyudmila [28]
3 years ago
11

Solve for X. Assume that lines which appear to be diameters are actual diameters. Show work pls.

Mathematics
1 answer:
Ahat [919]3 years ago
8 0

9514 1404 393

Answer:

  x = -6

Step-by-step explanation:

The three marked angles total 180°, the number of degrees in a semicircle.

  (x +51) +65 +70 = 180

  x = 180 -186 = -6 . . . . . . . . subtract 186 and simplify

The value of x is -6.

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Which numbers are the extremes of the proportion shown below?
wolverine [178]

Answer:

A 3 and 8

Step-by-step explanation:

if a/b=c/d, the extremes are "a" and "d". The means would then be "b" and "c"

8 0
2 years ago
Based on the triangle given, determine the trig ratio of the cos 0
likoan [24]

Answer:

cos theta = 4/5

Step-by-step explanation:

Since this is a right triangle

Cos theta = opp side/ hypotenuse

Cos theta = 8/10

cos theta = 4/5

4 0
3 years ago
Can someone help with #4<br><br> 15 points
BigorU [14]

I would check my math but 4/3 = 1.3 x 18= 24 divided by 2 for radius would be 12x12=144 x pie or 3.14 would be 452.16

4 0
4 years ago
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saul85 [17]

Answer:

I hope it helped u.

Step-by-step explanation:

7 0
4 years ago
Suppose a random sample of 200 Americans is asked to disclose whether they can order a meal in a foreign language. Describe the
taurus [48]

Answer:

The distribution of sample proportion Americans who can order a meal in a foreign language is,

\hat p\sim N(p,\ \sqrt{\frac{p(1-p)}{n}})

Step-by-step explanation:

According to the Central limit theorem, if from an unknown population large samples of sizes <em>n</em> > 30, are selected and the sample proportion for each sample is computed then the sampling distribution of sample proportion follows a Normal distribution.

The mean of this sampling distribution of sample proportion is:

 \mu_{\hat p}=p

The standard deviation of this sampling distribution of sample proportion is:

\sigma_{\hat p}=\sqrt{\frac{p(1-p)}{n}}

The sample size of Americans selected to disclose whether they can order a meal in a foreign language is, <em>n</em> = 200.

The sample selected is quite large.

The Central limit theorem can be applied to approximate the distribution of sample proportion.

The distribution of sample proportion is,

\hat p\sim N(p,\ \sqrt{\frac{p(1-p)}{n}})

3 0
3 years ago
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