2 years ago

What is the distance between (5,2) and (-3,4) on a coordinate plane

1 answer:

5 0

$\bf \textit{distance between 2 points}\\ \quad \\
\begin{array}{lllll}
&x_1&y_1&x_2&y_2\\
% (a,b)
&({{ 5}}\quad ,&{{ 2}})\quad 
% (c,d)
&({{ -3}}\quad ,&{{ 4}})
\end{array}\qquad 
% distance value
d = \sqrt{({{ x_2}}-{{ x_1}})^2 + ({{ y_2}}-{{ y_1}})^2}
\\\\\\
d=\sqrt{[-3-5]^2+[4-2]^2}$

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