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exis [7]
3 years ago
11

How to solve x+3=15 Using the inverse operation please help

Mathematics
2 answers:
torisob [31]3 years ago
5 0

\huge\textsf{Hey there!}

\large\textsf{x + 3 = 15}

\huge\text{SUBTRACT 3 to BOTH SIDES}

\large\textsf{x + 3 - 3 = 15 - 3}

\large\textsf{CANCEL out: 3 - 3 because that gives you 0}

\large\textsf{KEEP: 15 - 3 because it helps solve for x}

\large\textsf{15 - 3 = x}

\boxed{\boxed{\large\textsf{Answer: \huge \bf x = 12}}}\huge\checkmark

\large\text{Good luck on your assignment and enjoy your day!}

~\frak{Amphitrite1040:)}

GaryK [48]3 years ago
4 0

Answer:

x+3=15

  -3   -3

x=12

Step-by-step explanation:

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3 0
3 years ago
0.75h + 3 = 12 <br> What's the answer?
kykrilka [37]

Answer:

h = 12

General Formulas and Concepts:

<u>Pre-Algebra</u>

  • Order of Operations: BPEMDAS
  • Equality Properties

Step-by-step explanation:

<u>Step 1: Define equation</u>

0.75h + 3 = 12

<u>Step 2: Solve for </u><em><u>h</u></em>

  1. Subtract 3 on both sides:                    0.75h = 9
  2. Divide 0.75 on both sides:                  h = 12

<u>Step 3: Check</u>

<em>Plug in h into the original equation to verify it's a solution.</em>

  1. Substitute in <em>h</em>:                    0.75(12) + 3 = 12
  2. Multiply:                               9 + 3 = 12
  3. Add:                                     12 = 12

Here we see that 12 does indeed equal 12.

∴ h = 12 is a solution of the equation.

5 0
3 years ago
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