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2 years ago

13

HELP 76 POINTS IF YOU DO Which equations represent linear functions?

2 answers:

diamong [38]2 years ago

6 0

Answer: a,c,d

Step-by-step explanation:

asambeis [7]2 years ago

4 0

My answer would be A and D

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Pls help i give brainliest

GalinKa [24]

10,000 in the answer

3 0

2 years ago

There are three power plants [X, Y, Z] that at any given time each one either generates electricity or idles. Event A is that pl

insens350 [35]

We're told that

$P(A\cap B)=0.15$

$P(A\cup B)^C=0.06\implies P(A\cup B)=0.94$

$P(B\mid A)=P(B^C\mid A)=0.5$

where the last fact is due to the law of total probability:

$P(A)=P(A\cap B)+P(A\cap B^C)$

$\implies P(A)=P(B\mid A)P(A)+P(B^C\mid A)P(A)$

$\implies 1=P(B\mid A)+P(B^C\mid A)$

so that $B\mid A$ and $B^C\mid A$ are complementary.

By definition of conditional probability, we have

$P(B\mid A)=P(B^C\mid A)$

$\implies\dfrac{P(A\cap B)}{P(A)}=\dfrac{P(A\cap B^C)}{P(A)}$

$\implies P(A\cap B)=P(A\cap B^C)$

We make use of the addition rule and complementary probabilities to rewrite this as

$P(A\cap B)=P(A\cap B^C)$

$\implies P(A)+P(B)-P(A\cup B)=P(A)+P(B^C)-P(A\cup B^C)$

$\implies P(B)-[1-P(A\cup B)^C]=[1-P(B)]-P(A\cup B^C)$

$\implies2P(B)=2-[P(A\cup B)^C+P(A\cup B^C)]$

$\implies2P(B)=[1-P(A\cup B)^C]+[1-P(A\cup B^C)]$

$\implies2P(B)=P(A\cup B)+P(A\cup B^C)^C$

$\implies2P(B)=P(A\cup B)+P(A^C\cap B)\quad(*)$

By the law of total probability,

$P(B)=P(A\cap B)+P(A^C\cap B)$

$\implies P(A^C\cap B)=P(B)-P(A\cap B)$

and substituting this into $(*)$ gives

$2P(B)=P(A\cup B)+[P(B)-P(A\cap B)]$

$\implies P(B)=P(A\cup B)-P(A\cap B)$

$\implies P(B)=0.94-0.15=\boxed{0.79}$

8 0

2 years ago

All most done thanks for hanging in there

Ber [7]

Answer:

Angle CBE

Step-by-step explanation:

They share the same degree. Or are the same angle in a different place with a different name.

7 0

2 years ago

Read 2 more answers

Write an expression for the eighth partial sum of the series using summation notation

balandron [24]

Answer:

option B

Step-by-step explanation:

9/10 + 6/5 + 3/2...........

We find the difference between the terms

$\frac{6}{5} - \frac{9}{10}$

$\frac{12}{10} - \frac{9}{10} = \frac{3}{10}$

We will get the same difference when we subtract consecutive terms.

so , d= 3/10, a= 9/10

we find the formula for nth term

a_n = a+(n-1) d

$a_n = \frac{9}{10} + (n-1)\frac{3}{10}$

$a_n = \frac{9}{10} +\frac{3}{10}n-\frac{3}{10}$

$a_n = \frac{6}{10} +\frac{3}{10}n$

$a_n = \frac{3}{5} +\frac{3}{10}n$

we need to find eighth partial sum so we take n=1 to 8

sum of 8 terms ( $\frac{3}{5} +\frac{3}{10}n$ )

So option B is correct

4 0

2 years ago

Every Pint is 2 cups.Write an equation to express the total number of cups (Z) in (Y) pints.

IceJOKER [234]

Pints = y
Cups = z

2z = y

7 0

2 years ago