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2 years ago

HELP 76 POINTS IF YOU DO Which equations represent linear functions?

Mathematics

2 answers:

diamong [38]2 years ago

6 0

Answer: a,c,d

Step-by-step explanation:

asambeis [7]2 years ago

4 0

My answer would be A and D

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What is the reciprocal of each mixed number? Drag and drop the answer into the box to match each number.

Gnoma [55]

Hi there!!

First, we are going to find the improper fraction of each mixed number.

10 1/3 >>>>> 10*3+1=31 31/3

2 2/3 >>>>> 2*3+2=8. 8/3

5 1/3 >>>>>> 5*3+1 = 16. 16/3

TO find the reciprocal, we switch the numerator with the denominator.

31/3 changes to 3/31, 8/3 changes to 3/8, and finally 16/3 changes to 3/16.

Your answer is:

3/31
3/8
3/16

Hope this helps! Let me know if you have any questions:)

5 0

3 years ago

Use the Pythagorean theorem to find the distance between the points (1,1) and (5,7).?

Fynjy0 [20]

Check the picture below.

7 0

1 year ago

Factor the polynomials 2x4+4x3+6x2?

Shalnov [3]

Answer:x^2+2x+3

Step-by-step explanation:

I’m assuming you meant 2x^4+4x^3+6x^2...

So you can pull out 2x^2 from all of the polynomials...

And this equation isn’t able to be simplified anymore. Hope this helps!

5 0

3 years ago

On the 1st January 2014 Carol invested some money in a bank account.

Ghella [55]

Answer:

$\large \boxed{\text{\pounds 23 360.00}}$

Step-by-step explanation:

The formula for the accrued amount from compound interest is

$A = P \left(1 + \dfrac{r}{n}\right)^{nt}$

1. Amount in account on 1 Jan 2015

(a) Data:

a = £23 517.60

r = 2.5 %

n = 1

t = 1 yr

(b) Calculations:

r = 0.025

$\begin{array}{rcl}23517.60 & = & P\left (1 + \dfrac{r}{n}\right)^{nt}\\\\& = & P\left (1 + \dfrac{0.025}{1}\right)^{1\times1}\\\\& = & P (1 + 0.025)\\ & = & 1.025 P\\P & = & \dfrac{23517.60 }{1.025} \\\\& = & 22 944.00 \\\end{array}$

The amount that gathered interest was £22 944.00 but, before the interest started accruing, Carol had withdrawn £1000 from the account.

She must have had £23 944 in her account on 1 Jan 2015.

(2) Amount originally invested

(a) Data

A = £23 944.00

$\begin{array}{rcl}23 944.00 & = & 1.025 P\\P & = & \dfrac{23 944.00 }{1.025} \\\\& = & \mathbf{23 360.00} \\\end{array}\\\text{Carol originally invested $\large \boxed{\textbf{\pounds23 360.00}}$ in her account.}$

3. Summary

1 Jan 2014 P = £23 360.00

1 Jan 2015 A = 23 944.00

Withdrawal = <u> -1 000.00 </u>

P = 22 944.00

1 Jan 2016 A = £23 517.60

5 0

3 years ago

HELLLOOOO THIS IS DUE HELP

loris [4]

Answer:

RS=13

Step-by-step explanation:

RS+ST=RT

2w+1+w-1=18

3w=18

w=6

RS= 2w+1= 2(6)+1= 12+1= 13

7 0

2 years ago