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3 years ago

Find the distance between the points

Mathematics

2 answers:

Sonja [21]3 years ago

6 0

Answer:

Step-by-step explanation:

√(4^2+3^2)=5

Tasya [4]3 years ago

3 0

Answer:

5 units

Step-by-step explanation:

Calculate the distance d using the distance formula

d = $\sqrt{(x_{2}-x_{1})^2+(y_{2}-y_{1})^2 }$

with (x₁, y₁ ) = (2, 1) and (x₂, y₂ ) = (6, 4)

d = $\sqrt{(6-2)^2+(4-1)^2}$

= $\sqrt{4^2+3^2}$

= $\sqrt{16+9}$

= $\sqrt{25}$

= 5

You might be interested in

Solve the inequality −x/2<4

FinnZ [79.3K]

Isolate the x. First, multiply 2 to both sides

-x/2(2) < 4(2)

-x < 4(2)

-x < 8

Isolate the x. Divide - 1 to both sides (because you are dividing a negative number, flip the sign).

-x/ -1 < 8/-1

x > -8 is your answer

hope this helps

5 0

3 years ago

It cost 5 dollars for a child ticket and 8 dollars for a adult ticket. Total tickets sold were 110 bringing in 820 dollars? How

omeli [17]

Number of child tickets bought is 20

<h3>Solution:</h3>

Given that It cost 5 dollars for a child ticket and 8 dollars for a adult ticket

cost of each child ticket = 5 dollars

cost of each adult ticket = 8 dollars

Let "c" be the number of child tickets bought

Let "a" be the number of adult tickets bought

Total tickets sold were 110 bringing in 820 dollars

Number of child tickets bought + number of adult tickets bought = 110

c + a = 110 ----- eqn 1

Also we can frame a equation as:

Number of child tickets bought x cost of each child ticket + number of adult tickets bought x cost of each adult ticket = 820

$c \times 5 + a \times 8 = 820$

5c + 8a = 820 -------- eqn 2

Let us solve eqn 1 and eqn 2 to find values of "c" and "a"

From eqn 1,

a = 110 - c ------ eqn 3

Substitute eqn 3 in eqn 2

5c + 8(110 - c) = 820

5c + 880 - 8c = 820

-3c = - 60

c = 20

Therefore from eqn 3,

a = 110 - 20 = 90

a = 90

Therefore number of child tickets bought is 20

8 0

3 years ago

I need help plzz. Dilate this by 1/3

leva [86]

For this shape there are four points. The plotted ordered pairs are:
M = (3, 9)
N = (6, 0)
O = (3, 6)
P = (-3, 0)

All you have to do is multiply the BOTH x- and y-values by 1/3 on EACH ordered pair. And if it’s easier, you can divide by 3 as well. It’s the same thing.

M = (3, 9) = (3*1/3, 9*1/3) = (1, 3)
N = (6, 0) = (6*1/3, 0*1/3) = (2, 0)
O = (3, 6) = (3*1/3, 6*1/3) = (1, 2)
P = (-3, 0) = (-3*1/3, 0*1/3) = (-1, 0)

(1, 3) , (2, 0) , (1, 2) , and (-1, 0) are your points.

8 0

3 years ago

Read 2 more answers

:) help yuh yuh PLS HELP

pishuonlain [190]

Answer:

first box= $\sqrt{75}$ second box= $\sqrt{73}$