The binomial expansion:
a = 2y, b = 4 x^3, n = 4
( x )^3k = x^ 9
k = 3
Answer: the coefficient is
512.
Answer:
s = height above ground
s = 60 + 20 t - 4.9 t^2 (standard physics equation on earth)
at t = 0
s = 60 (clearly :)
now when does it hit the bleak earth?
That is when s = 0
4.9 t^2 - 20 t -60 = 0
solve quadratic and use the positive t (the negative t was back before you threw it if you had thrown it from the ground)
t = 6.09 or - 2.01
use t = 6.09
now to do the last part there are two obvious ways to get t at the peak
1. look for vertex of parabola
2. look for halfway between t = -2.01 and t = 6.09
I will do it the hard (11) waay by completing the square
4.9 t^2 - 20 t = -(s-60)
t^2 - 4.08 t = -.204 s + 12.2
t^2 - 4.08 t +2.04^2 = -.204 s +12.2 + 4.16
(t-2.04)^2 = -.204(s-80.2)
so
top at 80.2 meters at t = 2.04 s
===============
quick check on time
should be average of 6.09 and -2.01
=4.08 /2 = 2.04 check
Answer:
y = (-5/2)x + 27
Step-by-step explanation:
Use the point slope formula y = mx + b.
Replace m with -5/2, x with -8 and y with 7:
7 = (-5/2)(8) + b. Find the y-intercept, b:
7 = -20 = b, or b = 27
The equation of this line is y = (-5/2)x + 27.
Answer:
x = 2.25 or any number greater
Step-by-step explanation:
5x3 > 4 + 8 + x
Make them equal to each other to get x
5x3 = 4 + 8 + x
(5x)(3) = 12 + x
- x - 3 - 3 - x
4x = 9
x = 2.25
Once you get x plug it in to get the truth of the expression
A: the formula would be f(x) = P(R) ^T or f(x) = Principle(rate)^time
B: f(x) = 20,000(0.85)^5
C: = 8,874.10625
D: Yes, the final answer makes sense compared to the origional cost of the car in relation to the formula. As well, time decreases the value of a car, so for the cost to be so low only makes sense due to the cars decrease in value or an extended and elongated amount of time.
E: You can solve this equation graphically by plotting th point at 20,000 and then taking 85% of 20,000 and plotting it each time until you get to the fifth year.
