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lesya692 [45]
4 years ago
14

The sum of two consecutive integers is 59. Write an equation that models this situation and find the values of two integers.

Mathematics
1 answer:
Elza [17]4 years ago
4 0
Set on of the numbers as x. The consecutive integer to it would be x+1 (or x-1, which ever one you like. I'm going to use x+1 though). 

The sum would be 

x + (x+1)

Set it equal to 59. 

x+x+1=59
2x+1=59
2x=58
x=49

One integer is 49. The other integer, x+1, is 50.

Hope this helps!





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Mongoose McHuffy has a bike shop. He only has bicycles and tricycles in stock. In total he has 21 items in stock with a total of
olasank [31]

Answer:

12 bikes

9 tricycles

Step-by-step explanation:

x+y=21

2x+3y=51

x=-y+21

2(-y+21)+3y=51

-2y+42+3y=51

y+42=51

y=9

x=12

5 0
3 years ago
12 is what percent of 24? What percent of 35 is 7? What percent of 90 is 9? 20 out of 60 is what percent?​
irinina [24]

Answer:

12 is 50% of 24

7 is 20% of 35

9 is 10% of 90

20/60 is 33.33%

3 0
2 years ago
Read 2 more answers
What is the solution to the system of equations 2x-y=7 and y=2x+3
Yuri [45]
Make y the subject in both equations

2x-y=7

-y=-2x+7

y=2x-7

For the second equation

y=2x+3

The two equations are parallel because they have the same gradient or slope but different y intercepts.

This type of equations have no solution because they will never intersect.

NO SOLUTION

The correct answer is C
6 0
3 years ago
How to expand 3(2t+1)
Vlada [557]
Hey there :)

3 ( 2t + 1 )
We use what is called the distributive property to get rid of the parenthesis

We multiply the term outside the parenthesis by all terms inside
3 ( 2t ) + 3 ( 1 )

6t + 3 → Your answer
8 0
4 years ago
Hhelp pls lol i don't understand​
sladkih [1.3K]

Answer:

m∠1= 80

m∠2= 100

m∠3= 80

Step-by-step explanation:

Given: m∠1= 2x +40

m∠2= 2y +40

m∠3= x +2y

m∠1 +m∠2= 180 (adj. ∠s on a str. line)

2x +40 +2y +40= 180

2x +2y+ 80= 180

2x +2y= 180 -80

2x +2y= 100

2(x +y)= 100

x +y= 100 ÷2

x +y= 50 -----(1)

m∠1= m∠3 (vert. opp. ∠s)

2x +40= x +2y

2x -x +40= 2y

x= 2y -40 -----(2)

Substitute equation (2) into (1):

2y -40 +y= 50

3y= 50 +40

3y= 90

y= 90 ÷3

y= 30

Substitute y= 30 into equation (2):

x= 2(30) -40

x= 60 -40

x= 20

m∠1

= 2x +40

= 2(20) +40

= 40 +40

= 80

m∠2

= 2y +40

= 2(30) +40

= 60 +40

= 100

m∠3

= x +2y

= 20 +2(30)

= 20 +60

= 80

Alternatively, since m∠1= m∠3,

m∠3

= m∠1 (vert. opp. ∠s)

= 80

5 0
3 years ago
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