Question

F(x)=-x^2+8x-14 using quadratic formula

Answer 1

Answer:

$x=4-\sqrt{2}$ or $x=4+\sqrt{2}$

Step-by-step explanation:

Plug in given values of a, b, and c into the quadratic formula and solve for x:

$x=\frac{-b±\sqrt{b^{2}-4ac } }{2a}$

$x=\frac{-8±\sqrt{8^{2}-4(-1)(-14) } }{2(-1)}$

$x=\frac{-8±\sqrt{64-56 } }{-2}$

$x=\frac{-8±\sqrt{8} }{-2}$

$x=\frac{-8±2\sqrt{2} }{-2}$

$x=4±-\sqrt{2}$

Therefore, the roots are $x=4-\sqrt{2}$ or $x=4+\sqrt{2}$

Answer 2

Answer:

Were you looking for the x and y intercepts? The question is very misleading.

If you were the x intercepts are (4-√2,0), (4+√2,0)

And the y intercept is (0,−14)

If you did not mean this in your question please specify what you meant.