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3 years ago

Find the Area of the figure below, composed of a rectangle with two semicircles removed. Round to the nearest tenths place.

Mathematics

1 answer:

Allisa [31]3 years ago

6 0

Answer:

21.8

Step-by-step explanation:

hii so basically first we find the area of the 9 by 8 and subtract the area of the semicircles.

area of circles are πr^2, so in this situation

π4^2 which is 16π.

with this, the semicircle which is half a circle would give us

16π/2 which is 8π.

but then, we have two semicircles removed so we would have as an answer:

(9*8)-8π+8π

72-16π

then you would have to round so

16π is around 50.2

so 72-50.2 is 21.8

i hope this helped you <33

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Answer:

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Step-by-step explanation:

The volume of a cone is:

$V=\pi\ r^{2}\frac{h}{3}$

The volume of the first cone is, V₁ = 5 in³.

The volume of the second cone is, V₂ = 10 in³.

The two cones have the same base diameters.

This implies that the two radii are same, i.e. r₁ = r₂.

Compute the height of the second cone as follows:

$r_{1}=r_{2}$

$\frac{3\cdot V_{1}}{\pi\ h_{1}}=\frac{3\cdot V_{2}}{\pi\ h_{2}}$

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Answer:

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