3 years ago

What is 9+9+9+9+9+9+9++999+9+9+9+9+9+9+9+9+999999+99999++9+9+9+9=?

Mathematics

1 answer:

aliya0001 [1]3 years ago

3 0

Answer: I am going to die of boredom too

Step-by-step explanation: have an awesome amazing day

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If A( 1,8) B(2,6) and C(4,2) are three points, show that AC=3AB

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Answer:

see explanation

Step-by-step explanation:

Calculate AC and AB using the distance formula

d = $\sqrt{(x_{2}-x_{1})^2+(y_{2}-y_{1})^2 }$

with (x₁, y₁ ) = A(1,8) and (x₂, y₂ ) = C(4,2)

AC = $\sqrt{(4-1)^2+(2-8)^2}$

= $\sqrt{3^2+(-6)^2}$

= $\sqrt{9+36}$

= $\sqrt{45}$ = $\sqrt{9(5)}$ = 3 $\sqrt{5}$

Repeat with

(x₁, y₁ ) = A(1, 8) and (x₂, y₂ ) = B(2, 6)

AB = $\sqrt{(2-1)^2+(6-8)^2}$

= $\sqrt{1^2+(-2)^2}$

= $\sqrt{1+4}$

= $\sqrt{5}$

So AB = $\sqrt{5}$ and AC = 3 $\sqrt{5}$

Thus

AC = 3AB

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