Answer:
The vertical distance the ant have to walk is 8 units
Step-by-step explanation:
∵ The ant must be walk vertically and horizontally
∴ The distance from start point to end point will be as
a hypotenuse of a right angle triangle
∵ The ant would have to walk 6 units horizontally that
means one side of the right angle is 6 units
∵ The two points are apart by 10 units that means
the length of the hypotenuse is 10 units
∴ The vertical distance the ant would have to walk is
the length of the second side of the right angle
* By using Pythagoras Theorem:
∵ (hypotenuse)² = (horizontal leg)² + (vertical leg)²
∴ 10² = 6² + (vertical leg)²
∵ (vertical leg)² = 100 - 36 = 64
∴ Vertical leg = √64 = 8 units
∴ The vertical distance the ant have to walk is 8 units
9 times 2.75 equals 24.75
Answer:
m < amc = 54°
Step-by-step explanation:
< amb and < bmc are complementary angles whose sum equals 90°.
Therefore, to find the value of 2x°, we must first solve for x.
We can establish the following equality statement:
< amb + < bmc = < amc
< 2x° + (x + 9)° = 90°
Combine like terms:
2x° + x° + 9° = 90°
3x° + 9° = 90°
Subtract 9 from both sides:
3x° + 9° - 9° = 90° - 9°
3x = 81°
Divide both sides by 3 to solve for x:
3x/3 = 81°/3
x = 27°.
Since x = 27°, substitute its value into 2x° to find m < amc:
2x° = 2(27°) = 54°
Therefore, m < amc = 54°
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Answer:
B. 75
Step-by-step explanation:
1.5% of 5000 is 75
