Ask question

Ask question

All categories

3 years ago

7

What is the axis of symmtry

2 answers:

elixir [45]3 years ago

6 0

The middle of a parabola

belka [17]3 years ago

5 0

Answer:

The axis of symmetry of a parabola is a line about which the parabola is symmetrical.

Step-by-step explanation:

The axis of symmetry of a parabola is a line about which the parabola is symmetrical. When the parabola is vertical, the line of symmetry is vertical. When a quadratic function is graphed in the coordinate plane, the resulting parabola and corresponding axis of symmetry are vertical.

You might be interested in

6x-4y=24 in slope intercept form

Sav [38]

Use the slope-intercept form y=mx+b

3 0

3 years ago

Read 2 more answers

(14 plus 42)divided by 7plus4 to the 2power

Liono4ka [1.6K]

Answer:

Given info in numersical form:

(14+42)÷(7+4)²

= 56÷11²

= 56÷(11×11)

= 56÷121

= 0.46

7 0

3 years ago

What equation is equivalent to x^4-12x^2+36

vredina [299]

Simply solve the square.

(X^2-6)^2

7 0

4 years ago

Write each decimals as a fractions or a mixed number.<br><br> 26.3 and 7.104 >> help <

Amiraneli [1.4K]

Fraction:

26 3/10 and 7 104/1000

5 0

3 years ago

Line v passes through point [6.6] and is perpendicular to the graph of y= 3/4x - 11 line w is parallel to line v and passes thro

lbvjy [14]

Given:

The equation of a line is

$y=\dfrac{3}{4}x-11$

Line v passes through point (6,6) and it is perpendicular to the given line.

Line w passes through point (-6,10) and it is parallel to the line v.

To find:

The equation in slope intercept form of line w.

Solution:

Slope intercept form of a line is

$y=mx+b$ ...(i)

where, m is slope and b is y-intercept.

We have,

$y=\dfrac{3}{4}x-11$ ...(ii)

On comparing (i) and (ii), we get

$m=\dfrac{3}{4}$

So, slope of given line is $\dfrac{3}{4}$ .

Product of slopes of two perpendicular lines is -1.

$m_1\times m_2=-1$

$\dfrac{3}{4}\times m_2=-1$

$m_2=-\dfrac{4}{3}$

Line w is perpendicular to the given line. So, the slope of line w is $-\dfrac{4}{3}$ .

Slopes of parallel line are equal.

Line v is parallel to line w. So, slope of line v is also $-\dfrac{4}{3}$ .

Slope of line v is $-\dfrac{4}{3}$ and it passes thorugh (-6,10). So, the equation of line v is

$y-y_1=m(x-x_1)$

where, m is slope.

$y-10=-\dfrac{4}{3}(x-(-6))$

$y-10=-\dfrac{4}{3}(x+6)$

$y-10=-\dfrac{4}{3}x-\dfrac{4}{3}(6)$

$y-10=-\dfrac{4}{3}x-8$

Adding 10 on both sides, we get

$y=-\dfrac{4}{3}x-8+10$

$y=-\dfrac{4}{3}x+2$

Therefore the equation of line v is $y=-\dfrac{4}{3}x+2$ .

3 0

3 years ago