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Korolek [52]
3 years ago
12

Find the value of the cosine for ZA.

Mathematics
1 answer:
baherus [9]3 years ago
5 0

Answer:

C. \frac{8\sqrt{89}}{89}

Step-by-step explanation:

Cos A = Adj/Hyp

Reference angle = <A

Adjacent side = 8 ft

Hypotenuse = √(8² + 5²) = √89 (pythagorean theorem)

Thus:

Cos (A) = \frac{8}{\sqrt{89}}

Rationalize

Cos (A) = \frac{8 * \sqrt{89}}{\sqrt{89} * \sqrt{89}}

Cos (A) = \frac{8\sqrt{89}}{89}

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navik [9.2K]
<span> -21.8-(-18.3) (2 negative signs become positive)
=</span><span> -21.8 + 18.3
= - 3.5

Answer
- 3.5</span>
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3 years ago
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PLS HELP.<br> YOU WILL GET A GOOD DEED :)
Ludmilka [50]

Answer:

a) 6 2/5  

b) 13 1/2

Step-by-step explanation:

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3 years ago
140÷(x+9)+(x+4)² when x =1 show work​
Dmitrij [34]

Answer:

39

Step-by-step explanation:

If x=1, then it's equal to 140/(1+9, or 10)+(1+4, or 5)^2, and that is equal to 140/10+5^2, or 140/10+25, and 140/10=14, and 14+25=39

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Use the function below to find F(-4).<br><br> F(x) = 2^x
Amiraneli [1.4K]
To answer this item, note that what needs to be done is to substitute -4 to all x's in the equation. That is,
                     F(x) = 2^x
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4 0
3 years ago
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3.) SOLVE FOR X.
gayaneshka [121]

The value of x in the secants intersection is 1 units

The value of NM in the tangent and secant intersection is 51 units

<h3>How to find length when secant and tangent intersect?</h3>

The first question, two secant intersect outside the circle.

Therefore,

(6x + 8x)8x = (9 + 7)7

14x(8x) = 16(7)

112x² = 112

x² = 112 / 112

x = √1

x = 1

The second question, tangent and secant intersect,

Therefore,

(x + 3)² = (x - 3)(16 + x - 3)

(x + 3)² = (x - 3)(x + 13)

(x + 3)(x + 3) = (x - 3)(x + 13)

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x² + 9x + 9 = x² + 10x - 39

x² - x² + 9x - 10x = -39 - 9

-x = - 48

x = 48

NM = 48 + 3 = 51 units

learn more on secant and tangent here: brainly.com/question/12477905

#SPJ1

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