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3 years ago

9

True or False: The dependent variable is normally found on the horizontal axis of line graphs, bar graphs, and pictographs. True

False

1 answer:

matrenka [14]3 years ago

3 0

Answer:

False.

Step-by-step explanation:

That is false. For y = x^2 the dependent variable is y. The vertical axis is used for the dependent variable.

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Natali5045456 [20]

Answer:

The first number (or x value) of an ordered pair.

Step-by-step explanation:

Abscissa is the first number (or x value) of an ordered pair.

A coordinate plane is a way of locating points in a plane that consists of a horizontal and a vertical number line intersecting at the zeros.

Coordinates are an ordered pair, (x, y), that describes the location of a point in the coordinate plane.

Ordinate is the second number (or y value) of an ordered pair.

Origin is the point of intersection, (0, 0), of the axes in the coordinate plane.

A quadrant is a region in the coordinate plane.

X axis is the horizontal axis in the coordinate plane.

Y axis is the vertical axis in the coordinate plane.

4 0

3 years ago

Show that every triangle formed by the coordinate axes and a tangent line to y = 1/x ( for x > 0)

vfiekz [6]

Answer:

Step-by-step explanation:

given a point $(x_0,y_0)$ the equation of a line with slope m that passes through the given point is

$y-y_0 = m(x-x_0)$ or equivalently

$y = mx+(y_0-mx_0)$ .

Recall that a line of the form $y=mx+b$ , the y intercept is b and the x intercept is $\frac{-b}{m}$ .

So, in our case, the y intercept is $(y_0-mx_0)$ and the x intercept is $\frac{mx_0-y_0}{m}$ .

In our case, we know that the line is tangent to the graph of 1/x. So consider a point over the graph $(x_0,\frac{1}{x_0})$ . Which means that $y_0=\frac{1}{x_0}$

The slope of the tangent line is given by the derivative of the function evaluated at $x_0$ . Using the properties of derivatives, we get

$y' = \frac{-1}{x^2}$ . So evaluated at $x_0$ we get $m = \frac{-1}{x_0^2}$

Replacing the values in our previous findings we get that the y intercept is

$(y_0-mx_0) = (\frac{1}{x_0}-(\frac{-1}{x_0^2}x_0)) = \frac{2}{x_0}$

The x intercept is

$\frac{mx_0-y_0}{m} = \frac{\frac{-1}{x_0^2}x_0-\frac{1}{x_0}}{\frac{-1}{x_0^2}} = 2x_0$

The triangle in consideration has height $\frac{2}{x_0}$ and base $2x_0$ . So the area is

$\frac{1}{2}\frac{2}{x_0}\cdot 2x_0=2$

So regardless of the point we take on the graph, the area of the triangle is always 2.

6 0

3 years ago

8x – 3 = -19<br><br>Who give it fast they have branliest <br>Give the correct answer step by step

lakkis [162]

Answer:

<h2>x= -2</h2>

Step-by-step explanation:

$8x - 3 = - 19$

Collect like terms and simplify

$8x = - 19 + 3 \\ 8x = - 16$

Divide both sides of the equation by 8

$\frac{8x}{8} = \frac{ - 16}{8}$

Simplify

$x = - 2$

4 0

3 years ago

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Which of the following expressions entered into a graphing calculator will

Tanya [424]

Answer: B (0.17, 2.33)

Step-by-step explanation:

A P E X

5 0

3 years ago

What is five hundred eight thousand in standard form

bija089 [108]

500,000 + 8,000 = 508,000

8 0

3 years ago

Read 2 more answers