The coordinates of the 3 of the vértices of a parallelogram are (-7, 3), (-6, 1), and (-4, 5). What is the equation for the line
1 answer:
We know, opposite sides are parallelogram is parallel, therefore slopes are equal.
Slope of line one :
So, equation of other line passing through (-4,5) and have slope of -0.5 is :
y-5 = -0.5( x-(-4))
y-5 = -0.5x - 2
y + 1/2x = 3
2y + x = 6
Therefore, equation of line containing the (-4, 5) is 2y + x = 6.
Hence, this is the required solution.
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We have that
triangle ABC coordinates
A (0,2) B(2,4) C(0,0)
triangle DEF coordinates
D (2,0) E ( 4,4) F (4,2)
using a graph tool
see the attached figure
therefore
Line 1<span> Segment AC equals 2. Segment FE equals 2. Segment AC is congruent to segment FE
</span>so
Segment AC equals 2-------> is correct
Segment FE equals 2-----> is correct
Segment AC is congruent to segment FE------> is correct
<span>Line 2 ∠A ≅ ∠F------> is correct
</span>
<span>Line 3 Length of segment AB. A (0, 2) B (2, 4) d equals square root of quantity x sub 2 minus x sub 1 squared plus quantity y sub 2 minus y sub 1 squared, d equals square root of quantity 0 minus 2 all squared plus quantity 2 minus 4 all squared, d equals square root of negative 2 squared plus negative 2 squared, d equals square root of 4 plus 4, d equals square root of 8 segment AB = 2.83
</span>
find the distance AB
d=√[(4-2)²+(2-0)²]--------> d=√[4+4]-----> d=√8-----> d=2.83
AB=2.83
so
Line 3 is correct
<span>Line 4 Length of segment DE. D (2, 0) E (4, 4) d equals square root of quantity x sub 2 minus x sub 1 squared plus quantity y sub 2 minus y sub squared, d equals square root of quantity 2 minus 4 all squared plus quantity 0 minus 4 all squared, d equals square root of negative 2 squared plus negative 4 squared, d equals square root of 4 plus 16, then d equals square root of 20 segment DE = 4.47
</span>
find the distance DE
d=√[(4-0)²+(4-2)²]--------> d=√[16+4]-----> d=√20-----> d=4.47
DE=4.47
so
Line 4------> is correct
<span>Line 5 segment AB is congruent with segment DE
AB is not congruent with DE
so
Line 5 is not correct
therefore
the answer is
</span><span>the student make the first mistake in line 5</span><span>
</span>
triangle ABC coordinates
A (0,2) B(2,4) C(0,0)
triangle DEF coordinates
D (2,0) E ( 4,4) F (4,2)
using a graph tool
see the attached figure
therefore
Line 1<span> Segment AC equals 2. Segment FE equals 2. Segment AC is congruent to segment FE
</span>so
Segment AC equals 2-------> is correct
Segment FE equals 2-----> is correct
Segment AC is congruent to segment FE------> is correct
<span>Line 2 ∠A ≅ ∠F------> is correct
</span>
<span>Line 3 Length of segment AB. A (0, 2) B (2, 4) d equals square root of quantity x sub 2 minus x sub 1 squared plus quantity y sub 2 minus y sub 1 squared, d equals square root of quantity 0 minus 2 all squared plus quantity 2 minus 4 all squared, d equals square root of negative 2 squared plus negative 2 squared, d equals square root of 4 plus 4, d equals square root of 8 segment AB = 2.83
</span>
find the distance AB
d=√[(4-2)²+(2-0)²]--------> d=√[4+4]-----> d=√8-----> d=2.83
AB=2.83
so
Line 3 is correct
<span>Line 4 Length of segment DE. D (2, 0) E (4, 4) d equals square root of quantity x sub 2 minus x sub 1 squared plus quantity y sub 2 minus y sub squared, d equals square root of quantity 2 minus 4 all squared plus quantity 0 minus 4 all squared, d equals square root of negative 2 squared plus negative 4 squared, d equals square root of 4 plus 16, then d equals square root of 20 segment DE = 4.47
</span>
find the distance DE
d=√[(4-0)²+(4-2)²]--------> d=√[16+4]-----> d=√20-----> d=4.47
DE=4.47
so
Line 4------> is correct
<span>Line 5 segment AB is congruent with segment DE
AB is not congruent with DE
so
Line 5 is not correct
therefore
the answer is
</span><span>the student make the first mistake in line 5</span><span>
</span>