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Brums [2.3K]
3 years ago
8

What 8(9+16) plz i need help

Mathematics
2 answers:
pashok25 [27]3 years ago
4 0
If you add first then multiply
25x8
Fynjy0 [20]3 years ago
3 0
I think it would be 8*9+8*16 which would be 72+128= 200

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Solution:

we are given that

A school director Must randomly select 6 teachers to participate in a training session there are 30 teachers at the schoo. The order of selection does not matter.

As we know

6 teacheras can be selected out of 30 teacher in {30}_C_6 ways.

{30}_C_6=\frac{30!}{6!24!}\\
\\  {30}_C_6=\frac{25*26*27*28*29*30}{1*2*3*4*5*6}\\
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Hence the required number of ways is 593775.

7 0
2 years ago
What is the area? (IXL)
Zina [86]

Answer:

45 square meters

Step-by-step explanation:

we know that

The area of trapezoid is equal to

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h is the height of trapezoid (perpendicular distance between the parallel bases)

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substitute

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A=45\ m^2

3 0
3 years ago
Eden just bought a trough in the shape of a rectangular prism for her horses. She needs to know what volume of water to add to t
notsponge [240]

The volume of the trough is V(w) = w³ + 20w² - 429w and the rate of change of the volume over a width of 38 inches to 53 inches is 4695 in³/in

<h3>What is an equation?</h3>

An equation is an expression that shows the relationship between two or more variables and numbers.

Let w represent the width, hence:

length = w + 33, height = w - 13

Volume (V) = w(w + 33)(w - 13) = w³ + 20w² - 429w

V(w) = w³ + 20w² - 429w

Rate of change = dV/dw = 3w² + 40w - 429

When w = 38, dV/dw = 3(38)² + 40(38) - 429 = 5423

When w = 53, dV/dw = 3(53)² + 40(53) - 429 = 10118

Rate = 10118 - 5423 = 4695 in³/in

The volume of the trough is V(w) = w³ + 20w² - 429w and the rate of change of the volume over a width of 38 inches to 53 inches is 4695 in³/in

Find out more on equation at: brainly.com/question/2972832

#SPJ1

4 0
1 year ago
HUNTER filed for Chapter 13 bankruptcy in 2009. Even if she planned to take the maximum time allowed under Chapter 13 to repay h
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She must have planned No later than 2014
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