1 cubic meter = 100 cm * 100 cm * 100 cm = 1 x 10^6 cc
1 kilogram = 1,000 grams
13.6 g / cc
If we had a cubic meter of mercury, its mass would be (or it would "weigh") 13.6 * 1,000,000 = 13,600,000 grams or 13,600 kilograms.
And so its density would be 13,600 kg / cubic meter.
Answer:
Step-by-step explanation:
From equations (1) & (2), we find:
6x - 8 = - 3x +10
Plug x = 2 in equation (1)
y = 6(2)-8 = 12-8 =4
So,
Answer:
x = 30
Step-by-step explanation:
The perimeter is the sum of all of the sides of a shape. Therefore, because the sum is equivalent to 104 inches and we are given the lengths of all three sides, we can add the three sides together and set them equal to 104 in order to solve for x.
(x + 3) + (x + 4) + (x + 7) = 104 Drop the parentheses.
x + 3 + x + 4 + x + 7 = 104 Combine like terms (variables first!).
3x + 3 + 4 + 7 = 104 Now, combine constant terms.
3x + 14 = 104 Subtract 14 from both sides.
3x = 90 Divide by 3 on both sides of the equation.
x = 30
When <u>two</u> or <u>more</u> given triangles are <em>congruent</em>, this implies that the <u>measures</u> of their <em>corresponding</em> <u>angles</u> and <u>sides </u>are <u>equal</u>. So that the <em>additional information</em> required in the question is FG ≅ IJ.
When <u>two</u> or <u>more</u> given triangles are <em>congruent</em>, this implies that the <u>measures</u> of their <em>corresponding</em> <u>angles</u> and <u>sides </u>are <u>equal</u>. Thus the <u>congruent</u> <em>relations</em> of the <u>triangles </u>can be with respect to their <em>angles</em> or/ and <em>sides</em>.
The two given<u> triangles</u> in the question would be congruent with respect to the Side-Angle-Side (SAS) postulate if the condition below is true:
i.e FG ≅ IJ
For more clarifications on congruent triangles, visit: brainly.com/question/12077512
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