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spin [16.1K]
2 years ago
5

Nearest thousands 6,357

Mathematics
2 answers:
Klio2033 [76]2 years ago
4 0

Answer:

6,000

Step-by-step explanation:

Any number bellow 6,500 go's to 6,00 anything above go's to 7,000.

nasty-shy [4]2 years ago
3 0

Answer:

6,400

Step-by-step explanation:

yeah fam 6,400 is the answer

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What can be concluded about the spread of the histogram? A histogram titled Maria's Monthly Jogging has miles run on the x-axis
Rainbow [258]

Answer:

A

Step-by-step explanation:

6 0
3 years ago
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If Joan read 75 pages in 4 hours how long will it take her to read 250 pages
denis23 [38]
75/4=25 pages per hour, so, now we have to divide 250 by 25.

250/25=10

So, it would take Joan 10 hours to read 250 pages. :)
6 0
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I need help with this please
AnnZ [28]
Hi there! The answer is C.

The area of the square in the middle is the following:
length \: \times \: width \: = 5 \times 5 = 25
Hence, the area of the square is 25 cm^2.

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0.5 \times base \: \times \: height \: = 0.5 \times 5 \times 8 = 20
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3 years ago
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3y''-6y'+6y=e*x sexcx
Simora [160]
From the homogeneous part of the ODE, we can get two fundamental solutions. The characteristic equation is

3r^2-6r+6=0\iff r^2-2r+2=0

which has roots at r=1\pm i. This admits the two fundamental solutions

y_1=e^x\cos x
y_2=e^x\sin x

The particular solution is easiest to obtain via variation of parameters. We're looking for a solution of the form

y_p=u_1y_1+u_2y_2

where

u_1=-\displaystyle\frac13\int\frac{y_2e^x\sec x}{W(y_1,y_2)}\,\mathrm dx
u_2=\displaystyle\frac13\int\frac{y_1e^x\sec x}{W(y_1,y_2)}\,\mathrm dx

and W(y_1,y_2) is the Wronskian of the fundamental solutions. We have

W(e^x\cos x,e^x\sin x)=\begin{vmatrix}e^x\cos x&e^x\sin x\\e^x(\cos x-\sin x)&e^x(\cos x+\sin x)\end{vmatrix}=e^{2x}

and so

u_1=-\displaystyle\frac13\int\frac{e^{2x}\sin x\sec x}{e^{2x}}\,\mathrm dx=-\int\tan x\,\mathrm dx
u_1=\dfrac13\ln|\cos x|

u_2=\displaystyle\frac13\int\frac{e^{2x}\cos x\sec x}{e^{2x}}\,\mathrm dx=\int\mathrm dx
u_2=\dfrac13x

Therefore the particular solution is

y_p=\dfrac13e^x\cos x\ln|\cos x|+\dfrac13xe^x\sin x

so that the general solution to the ODE is

y=C_1e^x\cos x+C_2e^x\sin x+\dfrac13e^x\cos x\ln|\cos x|+\dfrac13xe^x\sin x
7 0
3 years ago
Help on this one. You will get 10 points
ad-work [718]

Answer:

A.true

Step-by-step explanation:

The domain of a quadratic function in standard form is always all real numbers, meaning you can substitute any real number for x. The range of a function is the set of all real values of y that you can get by plugging real numbers into x.

8 0
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