If -3 + i is a root of the polynomial function f(x), -3 - i must also be a root of f(x)
<h3>How to determine the true statement?</h3>
The root of the polynomial function is given as:
-3 + i
The above root is a complex root.
If a polynomial has a complex root, then the conjugate of the root is also a root of the function
The conjugate of -3 + i is -3 - i
Hence, if -3 + i is a root of the polynomial function f(x), -3 - i must also be a root of f(x)
Read more about polynomial functions at:
brainly.com/question/20896994
Answer:
30 days
Step-by-step explanation:
We solve the above question using Lowest Common Multiple Method.
Find and list multiples of each number until the first common multiple is found. This is the lowest common multiple.
Multiples of 6:
6, 12, 18, 24, 30, 36, 42
Multiples of 15:
15, 30, 45, 60
Therefore,
LCM(6, 15) = 30
Therefore, the NEXT time he will be cleaning his room and washing his windows on the same day is in 30 days time
Answer:
C. 2.8 miles per minute
Step-by-step explanation:
The mnemonic SOH CAH TOA reminds you that ...
... Tan = Opposite/Adjacent
In the relevant triangle, the side opposite the angle at the observer is the altitude of the airplane, 2 miles. The side adjacent is the horizontal distance to the airplane. At the first observation, that distance (d1) is ...
... tan(40°) = (2 mi)/d1
At the second observation, the horizontal distance to the airplane (d2) is ...
... tan(50°) = (2 mi)/d2
Solving for d1 and d2 and finding the difference (∆d), we have ...
... d1 = (2 mi)/tan(40°)
... d2 = (2 mi)/tan(50°)
... ∆d = d1 -d2 = (2 mi)(1/tan(40°) -1/tan(50°) ≈ 2·(1.1918 -0.8391) mi
... ∆d ≈ 2°0.3526 mi ≈ 0.7053 mi
This distance was flown by the plane in 15 seconds, so it will travel 4 times this distance in 60 seconds (1 minute).
... ∆d/∆t = (0.7053 mi)/(1/4 min) = 4·0.7053 mi/min ≈ 2.8 mi/min
Answer:
Step-by-step explanation:
m∠ABC + m∠BAC + m∠ACB = 180°
a + 2a + 6a = 180°
9a = 180°
a = 20°
m∠ABC = 20°
m∠BAC = 2 × 20° = 40°
m∠ACB = 6 × 20° = 120°
I think I can.
Let's do it together:
Let's call the number of buses 'B', and the number of vans 'V'.
(Pretty clever so far, don't you think ?)
OK. What do we know ?
-- Each bus holds 51 passengers. The number of passengers in 'B' buses is 51B.
-- A van holds 10 passengers. The number of passengers in 'V' vans is 10V.
-- The total number of passengers ... (51B + 10V) ... is 142.
-- The total number of vehicles ... (B + V) ... is 6, because there are 6 drivers.
Can you make a system of equations out of that information yet ?
How about this:
51B + 10V = 142
B + V = 6
I really think you can handle it from here.
=======================================
Multiply the 2nd equation by 10 :
51B + 10V = 142
10B + 10V = 60
Subtract the 2nd equation from the 1st one:
41B = 82
Divide each side by 41: <em> B = 2 buses</em>
2 buses . . . . 2 drivers . . . . 2 x 51 = 102 passengers
4 vans . . . . . 4 drivers . . . . . 4 x 10 = 40 passengers
6 vehicles . . . 6 drivers . . . . . 102 + 40 = 142 passengers