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Ulleksa [173]
3 years ago
12

I need helppp pleaseee!! like asap!!!

Mathematics
1 answer:
strojnjashka [21]3 years ago
4 0

Answer:

add me on snap johni_spurgeon and ill be able to help you with the problem

Step-by-step explanation:

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Mrs. Terrace cut a small birthday cake into 6 equal pieces for 6 children. One child was not hungry, so she gave the birthday bo
ELEN [110]

Missing part of question:

Draw a tape diagram to show how much cake each of the five children received.

Answer:

See attachment

Step-by-step explanation:

Given

Equal\ Pieces = 6

Children = 5

Required

Tape diagram to represent the scenario

Because one child is not hungry, the number of children to share the cake becomes 6.

So, first we calculate the share of each child.

Share = \frac{Pieces}{Children}

Share = \frac{6}{5}

Share = 1.2

See attachment for tape diagram

The tape diagram implies that:

5 * 1.2 = 6

or

\frac{6}{1.2} = 5

or

\frac{6}{5} = 1.2

4 0
3 years ago
5/2x-7=2/4x+14<br><br>a x = -6<br>b x = 6<br>c x = 8<br>d x = 12​
kykrilka [37]
The answer I got was x= 21/2
3 0
2 years ago
The list shows the score of each game completed at a bowling alley during a one-hour period. 90, 96, 120, 124, 130, 135, 140, 14
HACTEHA [7]
90, 96, 120, 124, 130, 135, 140, 145, 148, 290, 290. How would the data graphed on a horizontal number line appear to be clustered or skewed?
6 0
2 years ago
Plz help me with this question
solniwko [45]
The answer is 13/25 13 is odd so it can't be evenly divided by anything so it is in its simplest form
6 0
3 years ago
Pls help me not fail
nignag [31]

Answer:

D

Step-by-step explanation:

Using the Cosine rule to find AC

AC² = BC² + AB² - (2 × BC × AB × cosB )

      = 18² + 12² - ( 2 × 18 × 12 × cos75° )

      = 324 + 144 - 432cos75°

      = 468 - 111.8

      = 356.2 ( take the square root of both sides )

AC = \sqrt{356.2} ≈ 18.9

-----------------------------------------

Using the Sine rule to find ∠ A

\frac{18}{sinA} = \frac{18.9}{sin75} ( cross- multiply )

18.9 sinA = 18 sin75° ( divide both sides by 18.9 )

sinA = \frac{18sin75}{18.9} , then

∠ A = sin^{-1} ( \frac{18sin75}{18.9} ) ≈ 66.9°

4 0
3 years ago
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